978-0078027680 Chapter 4 Part 1

subject Type Homework Help
subject Pages 14
subject Words 4217
subject Authors John Cimbala, Robert Turner, Yunus Cengel

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4-1
Solutions Manual
for
Fundamentals of Thermal Fluid Sciences
5th Edition
Yunus A. Çengel, John M. Cimbala, Robert H. Turner
McGraw-Hill, 2017
Chapter 4
PROPERTIES OF PURE SUBSTANCES
PROPRIETARY AND CONFIDENTIAL
This Manual is the proprietary property of McGraw-Hill Education and protected by copyright and
other state and federal laws. By opening and using this Manual the user agrees to the following
restrictions, and if the recipient does not agree to these restrictions, the Manual should be promptly
returned unopened to McGraw-Hill Education: This Manual is being provided only to authorized
professors and instructors for use in preparing for the classes using the affiliated textbook. No
other use or distribution of this Manual is permitted. This Manual may not be sold and may not
be distributed to or used by any student or other third party. No part of this Manual may be
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without the prior written permission of McGraw-Hill Education.
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4-2
Pure Substances, Phase Change Processes, Property Diagrams
4-7C Yes.
Property Tables
4-10C The molar mass of gasoline (C8H18) is 114 kg/kmol, which is much larger than the molar mass of air that is 29
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4-3
4-11C Yes. Otherwise we can create energy by alternately vaporizing and condensing a substance.
of the selected reference state.
TfPT @,
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you are a student using this Manual, you are using it without permission.
0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0
0
100
200
300
400
500
600
700
s [kJ/kg-K]
T [C]
8600 kPa
2600 kPa
500 kPa
45 kPa
Steam
10
-4
10
-3
10
-2
10
-1
10
0
10
1
10
2
10
3
0
100
200
300
400
500
600
700
v [m3/kg]
T [C]
8600 kPa
2600 kPa
500 kPa
45 kPa
Steam
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4-7
10
-3
10
-2
10
-1
10
0
10
1
10
2
10
0
10
1
10
2
10
3
10
4
10
5
v [m3/kg]
P [kPa]
250 C
170 C
110 C
75 C
Steam
0500 1000 1500 2000 2500 3000
10
0
10
1
10
2
10
3
10
4
10
5
h [kJ/kg]
P [kPa]
250 C
170 C
110 C
75 C
Steam
0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0
0
500
1000
1500
2000
2500
3000
3500
4000
s [kJ/kg-K]
h [kJ/kg]
8600 kPa
2600 kPa
500 kPa
45 kPa
Steam
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4-8
4-23 Complete the following table for H2 O:
T, °C
P, kPa
v
, m3 / kg
140
361.53
0.05
155.46
550
0.001097
125
750
0.001065
500
2500
0.140
4-24E Complete the following table for H2 O:
T,
°
F P, psia u, Btu / lbm Phase description
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4-10
Solution for R22
T, ºF P, psia x u, Btu/lbm
Solution for ammonia
T, ºF P, psia x u, Btu/lbm
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4-12
4-29 A piston-cylinder device contains R-134a at a specified state. Heat is transferred to R-134a. The final pressure, the
volume change of the cylinder, and the enthalpy change are to be determined.
21
4-30E The temperature of R-134a at a specified state is to be determined.
/lbmft 0.6243
3
=
v
4-31 A rigid container that is filled with R-134a is heated. The final temperature and initial pressure are to be determined.
Analysis This is a constant volume process. The specific volume is
/kgm 1348.0
kg 10
m 348.1
3
3
21
==== m
V
vv
The initial state is determined to be a mixture, and thus the pressure is the
C40- @sat 1 kPa 51.25== °
The final state is superheated vapor and the temperature is determined by
interpolation to be
13)-A (Table
/kgm 1348.0
kPa 200
2
3
2
2
C66.3°=
=
=T
P
v
R-134a
-40°C
10 kg
1.348 m
3
v
2
1
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4-14
4-36E A spring-loaded piston-cylinder device is filled with R-134a. The water now undergoes a process until its volume
increases by 50%. The final temperature and the enthalpy are to be determined.
Analysis From Table A-11E, the initial specific volume is
/lbmft 5452.3)01143.04286.4)(80.0(01143.0
3
11
=+=+=
fgf
x
vvv
and the initial volume will be
33
11 ft 0.4609/lbm)ft 2lbm)(3.545 13.0( ===
With a 50% increase in the volume, the final volume will be
33
12 ft 0.6913)ft 4609.0(5.14.1 ===
The distance that the piston moves between the initial and final conditions is
4/ft) 1(
ft)4609.06813.0(
4/
2
3
2
12
ππ
D
A
p
VV
V
As a result of the compression of the spring, the pressure difference between the initial and final states is
in) 122934.0(lbf/in) 37(4
2
×
xk
xk
F
F30- @sat 1 == °
The final pressure is then
and the final specific volume is
lbm 13.0
ft 0.6813 3
3
2
2=== m
V
At this final state, the temperature and enthalpy are
/lbmft 318.5
psia 02.11
2
2
3
2
2
Btu/lbm 124.7
F104.7
=
°=
=
=
h
TP
v
Note that it is very difficult to get the temperature and enthalpy readings from Table A-13E accurately.
P
v
1
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4-15
4-37E A piston-cylinder device that is filled with water is cooled. The final pressure and volume of the water are to be
determined.
Analysis The initial specific volume is
/lbmft 4264.2
lbm 1
ft 4264.2
3
3
1
1
=== m
V
v
This is a constant-pressure process. The initial state is determined to be superheated
vapor and thus the pressure is determined to be
H
2
O
600°F
1 lbm
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4-17
4-42 A piston-cylinder device that is filled with R-134a is cooled at constant pressure. The final temperature and the change
of total internal energy are to be determined.
Analysis The initial specific volume is
/kgm 12322.0
kg 100
m 322.12
3
3
1
=== m
V
v
The initial state is superheated and the internal energy at this state is
R-134a
200 kPa
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4-18
4-43 A piston-cylinder device fitted with stops contains water at a specified state. Now the water is cooled until a final
pressure. The process is to be indicated on the T-
v
diagram and the change in internal energy is to be determined.
6)-A (TablekJ/kg 8.2808
C300
kPa 200
1
1
1
=
°=
=u
T
P
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4-19
4-45 The boiling temperature of water in a 5-cm deep pan is given. The boiling temperature in a 40-cm deep pan is to be
determined.
kPa sat@97.82boiling
4-46 A cooking pan is filled with water and covered with a 4-kg lid. The boiling temperature of water is to be determined.
Analysis The pressure in the pan is determined from a force balance on the lid,
C100.2
kPa 102.25@sat
°== TT
(Table A-5)
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4-20
4-47 Prob. 4-46 is reconsidered. Using a software, the effect of the mass of the lid on the boiling temperature of water
in the pan is to be investigated. The mass is to vary from 1 kg to 10 kg, and the boiling temperature is to be plotted against
the mass of the lid.
Analysis The problem is solved using EES, and the solution is given below.
"Given data"

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