Solution: Alternate Demonstration Problem
Chapter Ten
1a. Straight-line
The depreciation expense each year is equal to cost minus salvage
value divided by useful life. In this example the cost is $120,000, the
salvage value is $15,000, and the useful life is 5 years. Therefore,
D = (120,000 – 15,000) / 5
= 21,000 each year
1b. Units-of-production
The depreciation expense each year is equal to a rate [(cost minus
salvage) divided by total production] multiplied by the actual number
of units produced that year. In this example the rate would be $0.50
per widget, (120,000 – 15,000) / 210,000, and the depreciation expense
for each of the first three years would be:
D1= .50 x 80,000 = 40,000
D2= .50 x 50,000 = 25,000
D3= .50 x 30,000 = 15,000
1c. Double-declining balance
The depreciation expense each year is equal to a rate (twice the
straight-line rate divided by useful life) multiplied by the asset’s net
book value (cost minus accumulated depreciation) at the beginning
of the year. In this example the rate would be 2/5, or 40%, and the
depreciation expense for each of the first three years would be:
D1= .40 x 120,000 = 48,000
D2= .40 x 72,000 = 28,800
D3= .40 x 43,200 = 17,280