978-0073398242 Appendix B Solution Manual Part 5

subject Type Homework Help
subject Pages 9
subject Words 1170
subject Authors Brian Self, David Mazurek, E. Johnston, Ferdinand Beer, Phillip Cornwell

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page-pf1
PROBLEM B.25
A 2-mm thick piece of sheet steel is cut and bent into the machine
component shown. Knowing that the density of steel is 7850 kg/m3,
determine the mass moment of inertia of the component with
respect to each of the coordinate axes.
page-pf2
PROBLEM B.25 (Continued)
Panel 2:
z
page-pf3
PROBLEM B.26
A 2-mm thick piece of sheet steel is cut and bent into the
machine component shown. Knowing that the density of steel is
7850 kg/m
3
, determine the mass moment of inertia of the
component with respect to each of the coordinate axes.
page-pf4
PROBLEM B.26 (Continued)
123
() () ()
yy y y
II I I
22
4
(0.003880 0.064017)] kg m




2
2
(0.196160 0.044572 0.067897) kg m
2
0.308629 kg m
or
32
309 10 kg m

y
I
123
2
() () ()
(2.14305 kg)(0.35 m) (2.14305 kg) m




zz z z
II I I
4

or
32
154.4 10 kg m
z
I


page-pf5
PROBLEM B.27
A subassembly for a model airplane is fabricated from three pieces of 1.5-
mm plywood. Neglecting the mass of the adhesive used to assemble the
three pieces, determine the mass moment of inertia of the subassembly
with respect to each of the coordinate axes. (The density of the plywood
is
3
780 kg/m .)
page-pf6
PROBLEM B.27 (Continued)
123
2
() () ()
18 3




yy y y
II I I
1(21.0600 10 kg)[(0.3) (0.12) ] m
62
[(105.300 210.600) (122.148 244.296)
(47.637)] 10 kg m


62
(315.900 366.444 47.637) 10 kg m

62
page-pf7
PROBLEM B.28
A section of sheet steel 0.03 in. thick is cut and bent into the
sheet metal machine component shown. Determine the mass
moment of inertia of the component with respect to each of the
coordinate axes. (The specific weight of steel is 490 lb/ft3.)
page-pf8
Copyright © McGraw-Hill Education. Permission required for reproduction or display.
PROBLEM B.28 (Continued)
Plate 2 in x-z plane:
Note: By Eqn. 9.38,
66
'
55.728 10 396.29 10
yuv
III


2
2
6 2
761.62 10 lb ft s
y
y
I





Finally, total for both plates 1 and 2 gives,
12
66
594.43 10 761.62 10
yy y
III

32
page-pf9
PROBLEM B.29
A framing anchor is formed of 0.05-in.-thick galvanized steel. Determine the
mass moment of inertia of the anchor with respect to each of the coordinate
axes. (The specific weight of galvanized steel is
3
470 lb/ft .)
page-pfa
PROBLEM B.29 (Continued)
62 2 22
1(2006.14 10 lb s /ft)[(4.75) (2) ] in
18

[(23.578 70.735) (0.550 82.490)

x
123
62 2
22
() () ()
1(3325.97 10 lb s /ft)(2.25 in.)
12
212 in.
yy y y
II I I



62 2 22
1(950.28 10 lb s /ft)[(2.25) (1) ] in
12

22
62 2 2
18
11 ft



62
[(9.744 29.232) (3.334 10.002)
(3.096 76.720)] 10 lb ft s



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