7-139 Air is heated by an array of electrical heating elements. The rate of heat transfer to air and the exit temperature of air
are to be determined.
Assumptions 1 Steady operating conditions exist.
Properties The exit temperature of air, and thus the mean temperature, is not known. We evaluate the air properties at the
assumed mean temperature of 35C (will be checked later) and 1 atm (Table A-15):
k = 0.02625 W/m-K = 1.145 kg/m3
cp =1.007 kJ/kg-K Pr = 0.7268
= 1.89510-5 kg/m-s Prs = Pr@ Ts = 0.6937
Also, the density of air at the inlet temperature of 25C (for use in the mass flow rate calculation at the inlet) is
i = 1.184
kg/m3.
Analysis It is given that D = 0.012 m, SL = ST = 0.024 m, and V = 8 m/s. Then the maximum velocity and the Reynolds
number based on the maximum velocity become
m/s 16m/s) 8(
1224
24
max =
−
=
−
=V
DS
S
V
T
T
600,11
skg/m 10895.1
m) m/s)(0.012 16)(kg/m 145.1(
Re 5
3
max =
== −
DV
D
The average Nusselt number is determined using the proper relation from Table 7-2 to be
55.88)6937.0/7268.0()7268.0()600,11(27.0
)Pr(Pr/PrRe27.0Nu
25.036.063.0
25.036.063.0
==
=sDD
This Nusselt number is applicable to tube banks with NL > 16. In our case the number of rows is NL = 3, and the
corresponding correction factor from Table 7-3 is F = 0.86. Then the average Nusselt number and heat transfer coefficient
for all the tubes in the tube bank become
15.76)55.88)(86.0(NuNu ,=== DND F
L
C W/m6.166
m 0.012
C) W/m02625.0(15.76 2
,=
== D
kNu
hL
ND
The total number of tubes is N = NL NT = 34 = 12. The heat transfer surface area and the mass flow rate of air (evaluated at
the inlet) are
2
m 09048.0 m) m)(0.200 012.0(12 ===
DLNAs
kg/s 1819.0m) m)(0.200 024m/s)(4)(0. 8)(kg/m 184.1()( 3==== LSNVmm TTii
Then the fluid exit temperature, the log mean temperature difference, and the rate of heat transfer become
C67.50
C)J/kg kg/s)(1007 (0.1819
C) W/m6.166)(m 09048.0(
exp)25350(350exp)(
22
=
−−−=
−−−=
p
s
isse cm
hA
TTTT
C0.312
)]67.50350/()25350ln[(
)67.50350()25350(
)]/()ln[(
)()( =
−−
−−−
=
−−
−−−
=
esis
esis
lm TTTT
TTTT
T
W4703=== )C0.312)(m C)(0.09048 W/m6.166(22
lmsThAQ