Dynamics 2e 1567
Problem 7.78
An inextensible cord of negligible mass is wound around a homogeneous
circular object. Assume that the cord is pulled to the right while remain-
ing horizontal, and determine the value of the object’s mass moment of
inertia
IG
, such that the object rolls without slip no matter how large the
tension in the cord. What is the shape of such an object?
Solution
The FBD of the circular object as it is being pulled by a force
P
is shown on the
right.
Balance Principles.
Based on the FBD shown, the Newton-Euler equations for
the object are
XFxW FCPDmaGx ;(1)
XFyWNmg DmaGy ;(2)
XMGW PR FR DIG˛o;(3)
where ˛ois the angular acceleration of the object and its unknown mass moment of inertia is IG.
Force Laws. For the object to roll without slip we must have
jFj sjNj:(4)
Kinematic Equations. Since the object rolls without slip, we have
aGx D R˛oand aGy D0: (5)
Computation.
Substituting the kinematic equations into the Newton-Euler equations and treating the force
P
and the mass moment of inertia
IG
as a given parameters, we obtain the following system of three equations
in the three unknowns N,F, and ˛o
FCPD mR˛o; N mg D0; and PR FR DIG˛o
the solution of which is
NDmg; F DIGmR2
IGCmR2P; and ˛oD 2PR
IGCmR2:(6)
This expression for the force
F
shows that, unless
F
were completely independent of
P
, for arbitrarily large
values of
P
the force
F
would take on corresponding large values that would cause the no slip condition
jFj sjNj
to be violated. In order for the force
F
to be independent of
P
, the numerator of the expression
for Fmust be equal to zero, that is,
IGDmR2:
The only homogeneous circular symmetric object with mass moment of inertia equal to
mR2
is a thin circular
ring of radius R.
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