792 Solutions Manual
Problem 4.90
Revisit Example 4.7 on p. 266 and determine the maximum height reached by the pole vaulter, but this
time include the mass of the pole in your analysis. To solve the problem, use the following data: the
maximum speed achieved by the pole vaulter and pole at the time the vault begins is
vmax D34:19 ft=s
;
the pole vaulter is
6ft
tall with mass center at
55
% of body height (as measured from the ground) and
weighs
190 lb
; the pole is uniform, has a weight of
5:8 lb
, and is
17:1 ft
long. In addition, assume that as
the pole vaulter sprints before the vault, the pole is carried horizontally at the same height as the vaulter’s
center of mass relative to the ground. Explain why the vault height you find when the pole is included is
higher than the vault height determined in Example 4.7, when the pole was not included.
Solution
of McGraw-Hill, and must be surrendered upon request of McGraw-Hill. Any duplication or distribution, either in print or electronic form, without the
permission of McGraw-Hill, is prohibited.