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Problem 8.10
A hacksaw for cutting metal is shown. Assume contact between the frame
ABC
and the handle assembly occurs at points
B
and
C
only, neglect friction,
and neglect the size of the pin and notch at point
B
. If the blade is tensioned
to
100 lb
, determine the internal forces acting on: Cross sections
D
,
E
, and
F
,
where cross section Dis located immediately above point A.
Statics 2e 1167
We take a cut through cross section
F
and draw the FBD to the
right of the cross section to determine the internal forces.
Problem 8.11
A hacksaw for cutting metal is shown. Assume contact between the frame
ABC
and the handle assembly occurs at points
B
and
C
only, neglect friction,
and neglect the size of the pin and notch at point
B
. If the blade is tensioned to
100 lb
, determine the internal forces acting on: Cross sections
G
,
H
,
I
, and
J
,
where cross sections
H
and
I
are located immediately to the right and left of
point
B
, respectively, and cross section
J
is immediately to the right of point
C.
(17)
Summary:
NHD 100 lb; VHD0; MHD 275 in:lb:(18)
Problem 8.12
A weight
WD2kN
is supported by a cable that passes over frictionless pulleys
at
D
and
F
. The cable is attached to a winch at
G
, and cable segment
DG
is vertical. Member
ABC
is built in at
A
, and members
ABC
,
DCEF
, and
BE
are attached using pins at points
B
,
C
, and
E
. Neglecting the weights of
individual members, determine the internal forces acting on: Cross sections
H
and
I
, located immediately to the left of point
F
and the right of point
E
,
respectively.
W
GA
B
CE
FD
K
Q
JHI
P
LO
R
1.6 0.9 2.8
1.2
2.6
All dimensions are in meters.
0.2 0.2
Problem 8.13
A weight
WD2kN
is supported by a cable that passes over frictionless pulleys
at
D
and
F
. The cable is attached to a winch at
G
, and cable segment
DG
is vertical. Member
ABC
is built in at
A
, and members
ABC
,
DCEF
, and
BE
are attached using pins at points
B
,
C
, and
E
. Neglecting the weights of
individual members, determine the internal forces acting on: Cross sections
J
and
K
, located immediately to the left of point
E
and the right of point
C
,
respectively.
W
GA
B
CE
FD
K
Q
JHI
P
LO
R
1.6 0.9 2.8
1.2
2.6
All dimensions are in meters.
0.2 0.2
Solution
1172 Solutions Manual
We take a cut through cross section
J
and draw the FBD to
the right of the cross section to determine the internal forces.
We take a cut through cross section
K
and draw the FBD
to the right of the cross section to determine the internal
forces.
Problem 8.14
A weight
WD2kN
is supported by a cable that passes over frictionless pulleys
at
D
and
F
. The cable is attached to a winch at
G
, and cable segment
DG
is vertical. Member
ABC
is built in at
A
, and members
ABC
,
DCEF
, and
BE
are attached using pins at points
B
,
C
, and
E
. Neglecting the weights of
individual members, determine the internal forces acting on: Cross sections
L
and
O
, located immediately to the left of point
C
and the right of point
D
,
respectively.
W
GA
B
CE
FD
K
Q
JHI
P
LO
R
1.6 0.9 2.8
1.2
2.6
All dimensions are in meters.
0.2 0.2
Problem 8.15
A weight
WD2kN
is supported by a cable that passes over frictionless pulleys
at
D
and
F
. The cable is attached to a winch at
G
, and cable segment
DG
is vertical. Member
ABC
is built in at
A
, and members
ABC
,
DCEF
, and
BE
are attached using pins at points
B
,
C
, and
E
. Neglecting the weights of
individual members, determine the internal forces acting on: Cross sections
Q
and P, located immediately below and above point B, respectively.
W
GA
B
CE
FD
K
Q
JHI
P
LO
R
1.6 0.9 2.8
1.2
2.6
All dimensions are in meters.
0.2 0.2
Problem 8.16
A weight
WD2kN
is supported by a cable that passes over frictionless pulleys
at
D
and
F
. The cable is attached to a winch at
G
, and cable segment
DG
is vertical. Member
ABC
is built in at
A
, and members
ABC
,
DCEF
, and
BE
are attached using pins at points
B
,
C
, and
E
. Neglecting the weights of
individual members, determine the internal forces acting on: Cross section
R
located at the midpoint of member
BE
. Also determine the internal forces (i.e.,
the reactions) at the built-in support at A.
W
GA
B
CE
FD
K
Q
JHI
P
LO
R
1.6 0.9 2.8
1.2
2.6
All dimensions are in meters.
0.2 0.2
Problem 8.17
A machine for lifting heavy objects on an assembly line is shown. It consists of a
straight member
ABC
, a quarter-circular member
CDE
, and a hydraulic cylinder
BD
. In the position shown, the hydraulic cylinder is vertical. If
WD800 lb
, and
neglecting the weight of the components of the machine, determine the internal
forces acting on: Cross sections
F
and
G
, located immediately to the left of point
Aand to the right of point B, respectively.
Problem 8.18
A machine for lifting heavy objects on an assembly line is shown. It consists of a
straight member
ABC
, a quarter-circular member
CDE
, and a hydraulic cylinder
BD
. In the position shown, the hydraulic cylinder is vertical. If
WD800 lb
, and
neglecting the weight of the components of the machine, determine the internal
forces acting on: Cross sections
H
and
I
, located immediately to the left of point
Band to the right of point C, respectively.
Problem 8.19
A machine for lifting heavy objects on an assembly line is shown. It consists of a
straight member
ABC
, a quarter-circular member
CDE
, and a hydraulic cylinder
BD
. In the position shown, the hydraulic cylinder is vertical. If
WD800 lb
, and
neglecting the weight of the components of the machine, determine the internal
forces acting on: Cross sections
J
and
K
, located immediately above point
C
and
below and to the left of point D, respectively.
(12)
(14)
Problem 8.20
A machine for lifting heavy objects on an assembly line is shown. It consists of a
straight member
ABC
, a quarter-circular member
CDE
, and a hydraulic cylinder
BD
. In the position shown, the hydraulic cylinder is vertical. If
WD800 lb
, and
neglecting the weight of the components of the machine, determine the internal
forces acting on: Cross sections
L
and
M
, located immediately to the right and
above point Dand to the left of point E, respectively.
(5)
(7)
1182 Solutions Manual
Problem 8.21
Two structural members are shown; one is straight and the other is semicircular.
Neglect the weight of the members.
(a)
For the straight member, show that the internal forces acting on cross
section Care VD0,ND P, and MD0.
(b)
For the semicircular member, show that the internal forces acting on cross
section Care VD Pcos ,ND Psin , and MD Pr sin .
Problem 8.22
Both the straight and semicircular members shown in Fig. P8.22 are two-force
members, and hence either can be used as members of a truss. However, it
is most common that truss members are straight. Compare the answers to
Prob. 8.21 (which are given in the problem description) to argue why straight
truss members are preferable to curved truss members.
Note:
Concept problems
are about explanations, not computations.
Problem 8.23
Determine the internal forces acting on:
Cross section Kin Fig. 1 of Example 8.3 on p. 499.
