Exam
Name___________________________________
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Match the inequality to its graph.
1)
y 6x
1)
A)
B)
C)
D)
1
2)
x + 4y 3
2)
A)
B)
C)
D)
2
Choose the graph that matches the equation.
3)
–2x + 6y =2
3)
A)
B)
C)
D)
3
Match the inequality to its graph.
4)
3x + 5y –15
4)
A)
B)
C)
D)
4
5)
x – y > –3
5)
A)
B)
C)
D)
5
6)
3x + y 6
6)
A)
B)
C)
D)
6
7)
–2x – 4y 8
7)
A)
B)
C)
D)
7
8)
x 2
8)
A)
B)
C)
D)
8
9)
y < –4x + 1
9)
A)
B)
C)
D)
9
10)
y < –3
10)
A)
B)
C)
D)
10
Choose the graph that matches the equation.
11)
2x – y =2
11)
A)
B)
C)
D)
11
Match the inequality to its graph.
12)
x + y < –6
12)
A)
B)
C)
D)
12
Graph.
13)
4x +3y =12
13)
A)
B)
C)
D)
On the coordinate plane below, plot the points with the given coordinates.
13
14)
A(2, 1), B(–5, 1)
14)
A)
B)
C)
D)
14
Graph and shade the given inequality.
15)
3x + 5y –15
15)
A)
B)
C)
D)
15
Find the x– and y–intercepts for the equation. Then graph the equation.
16)
y = –2x
16)
A)
x–intercept: (0, 0), y–intercept: (0, 0)
B)
x–intercept: (0, 0), y–intercept: (0, 0)
C)
x–intercept: (0, 0), y–intercept: (0, 0)
D)
x–intercept: (0, 0), y–intercept: (0, 0)
16
Complete the table for the equation.
17)
y + 2x = –6
x y
–76
0
17)
A)
x y
–7 8
–6 6
0–6
B)
x y
–7–7
–6 6
0–6
C)
x y
–7 8
8 6
0 6
D)
x y
–7 8
–6 6
0 0
Solve the problem.
18)
A space heater can raise the temperature in a room by 4°F every 3 minutes. The temperature in the
room was 68°F after the heater had been running for 6 minutes.
(i) Write as a linear equation in slope–intercept form the relationship between the time that the
heater has been running and the temperature in the room.
(ii) Explain how you could have predicted whether the slope of the graph of this equation is
positive or negative.
18)
A)
(i) y =3
4x +60
(ii) As the amount of time the space heater is left on increases, the temperature of the room
increases, which implies a positive slope.
B)
(i) y =3
4x –60
(ii) As the amount of time the space heater is left on increases, the temperature of the room
increases, which implies a positive slope.
C)
(i) y =4
3x –60
(ii) As the amount of time the space heater is left on increases, the temperature of the room
increases, which implies a positive slope.
D)
(i) y =4
3x +60
(ii) As the amount of time the space heater is left on increases, the temperature of the room
increases, which implies a positive slope.
17
Graph the equation.
19)
y = –7– x
19)
A)
B)
C)
D)
Graph.
18
20)
y =1
9x +7
9
20)
A)
B)
C)
D)
19
Graph the line on the coordinate plane using the given information.
21)
Passes through (–3, –8) and m =4
21)
A)
B)
C)
D)
Solve the problem.
20
22)
Suppose that the speed of a car, measured in miles per hour (mph), is monitored for some short
period of time after the driver applies the brakes. The following table relates the speed of the car to
the amount of time, measured in seconds (sec), elapsed from the moment that the brakes are
applied. Plot this information on the coordinate plane below. What is happening to the speed of the
car during this time frame?
TIME
(seconds) SPEED
(mph)
249
434
624
814
10 9
22)
A)
The speed of the car decreased as time
elapsed.
B)
The speed of the car decreased as time
elapsed.
C)
The speed of the car increased as time
elapsed.
D)
The speed of the car increased as time
elapsed.
21
Complete the ordered pairs. Then graph the equation by plotting the points and drawing a line through them.
23)
y = – 1
2x – 2 (0, ), (2, ), (–2, )
23)
A)
(0, 2), (2, 1), (–2, 3)
B)
(0, –2), (2, –3), (–2, –1)
C)
(0, 0), (2, –1), (–2, 1)
D)
(0, –2), (2, –1), (–2, –3)
22
Graph using the slope and the y–intercept.
24)
y = –2x +6
24)
A)
B)
C)
D)
Find the x– and y–intercepts for the equation. Then graph the equation.
23
25)
y =3
4x –21
25)
A)
x–intercept: (–28, 0), y–intercept: (0, 21)
B)
x–intercept: (21, 0), y–intercept: (0, –21)
C)
x–intercept: (–28, 0), y–intercept: (0, –21)
D)
x–intercept: (28, 0), y–intercept: (0, –21)
24
Solve the problem.
26)
Suppose that during a certain step in a chemical manufacturing process the amount of chlorine
dissolved in a solution, measured in parts per million (ppm), is related to the elapsed time
measured from the beginning of the step. Use the following table as a representation of this
relationship. Write the data from the table as ordered pairs (x, y), where x represents the time and y
represents the amount dissolved.
TIME
(minutes) AMOUNT DISSOLVED
(ppm)
416.0
818.4
12 20.4
16 22.4
20 24.2
26)
A)
(1, 16.0), (2, 18.4), (3, 20.4), (4, 22.4), (5, 24.2)
B)
(0, 16.0), (4, 18.4), (8, 20.4), (12, 22.4), (16, 24.2)
C)
(4, 16.0), (8, 18.4), (12, 20.4), (16, 22.4), (20, 24.2)
D)
(16.0, 4), (18.4, 8), (20.4, 12), (22.4, 16), (24.2, 20)
Identify the quadrant in which the point is located.
27)
(–20, 17)
27)
A)
Quadrant II
B)
Quadrant III
C)
Quadrant I
D)
Quadrant IV
25
Graph and shade the given inequality.
28)
4x + y –6
28)
A)
B)
C)
D)
26
Decide whether the slope is positive, negative, zero, or undefined.
29)
29)
A)
Zero
B)
Undefined
C)
Negative
D)
Positive
Write the equation in slope–intercept form.
30)
3x – 10y = –6
30)
A)
y =3
10x +3
5
B)
y = – 3
10x +3
5
C)
y =10
3x – 2
D)
y = 3x + 11
Solve the problem.
31)
If a car travels at a constant speed, which graph best represents the speed of the car?
31)
A)
Graph B
B)
Graph D
C)
Graph C
D)
Graph A
27
Complete the table for the equation.
32)
y = – 3
2x +8
x y
16
3
811
32)
A)
x y
16
30
8–4
–211
B)
x y
16
316
8 4
–211
C)
x y
16
316
8–4
211
D)
x y
16
30
8 4
211
Solve the problem.
33)
A deep sea diving bell is being lowered at a constant rate. After 9 minutes, the bell is at a depth of
300 feet. After 45 minutes the bell is at a depth of 1600 feet. Write a linear equation in point–slope
form that gives the relationship between the time spent lowering the diving bell and the depth that
the bell has reached. Round the slope to the nearest tenth.
33)
A)
y –300=35.6(x –9) or y –1600 =35.6(x –45)
B)
y –300=0.03(x –9) or y –1600 =0.03(x –45)
C)
y –300=28.9(x –9) or y –1600 =28.9(x –45)
D)
y –300=36.1(x –9) or y –1600 =36.1(x –45)
Find the coordinates of the labeled points.
34)
34)
A)
E(–7, 4); G(–2, –7)
B)
E(–7, 4); G(–7, –2)
C)
E(–7, –2); G(4, –2)
D)
E(4, 2); G(–2, –7)
Decide if the given ordered pair is a solution to the inequality.
35)
y <1
3x – 2: (9, 0)
35)
A)
Yes
B)
No
28
Find the slope and the y–intercept of the line.
36)
y =8
36)
A)
Slope 0; y–intercept (0, 0)
B)
Slope 8; y–intercept (0, 0)
C)
Slope undefined; y–intercept (0, 8)
D)
Slope 0; y–intercept (0, 8)
On the coordinate plane below, plot the points with the given coordinates.
37)
A(–3, –5), B(–6, 2)
37)
A)
B)
C)
D)
29
38)
A(1, –5), B(–2, 1)
38)
A)
B)
C)
D)
Find an equation in slope–intercept form of the line satisfying the specified conditions.
39)
Passing through the points (–2, –9) and (–4, –13)
39)
A)
y =2x + 5
B)
y = –2x – 5
C)
y =2x – 5
D)
y = –2x + 5
30
Complete the ordered pairs. Then graph the equation by plotting the points and drawing a line through them.
40)
y – 6 = x (0, ), ( , 0), (1, )
40)
A)
(0, 6), (6, 0), (1, 5)
B)
(0, 6), (–6, 0), (1, 7)
C)
(0, –6), (6, 0), (1, –5)
D)
(0, –6), (–6, 0), (1, –7)
Find the slope and the y–intercept of the line.
41)
6x + 5y =49
41)
A)
Slope 6
5; y–intercept 0, 49
5
B)
Slope –5
6; y–intercept 0, 5
49
C)
Slope 5
6; y–intercept 0, 5
49
D)
Slope –6
5; y–intercept 0, 49
5
Solve the problem.
42)
On December 31 the depth, D, of snow at the base of a ski resort was 70 inches. The depth
decreases in a linear fashion by 2 inches per day during the following month of January.
(i) Write an equation for D after x days.
(ii) Graph the equation found in part (i).
(iii) Use the graph to estimate the depth of snow on January 30th.
42)
31
A)
(i) D = –x +70
(ii)
(iii) 40 in.
B)
(i) D = –2x +70
(ii)
(iii) 15 in.
C)
(i) D = –2x +70
(ii)
(iii) 10 in.
D)
(i) D = –x +70
(ii)
(iii) 18 in.
32
Find the coordinates of the labeled points.
43)
43)
A)
A(2, 3); B(5, –3)
B)
A(2, 5); B(3, 5)
C)
A(2, 3); B(–3, 5)
D)
A(3, 20); B(5, –3)
33
Find the x– and y–intercepts for the equation. Then graph the equation.
44)
–5x – 10y =10
44)
A)
x–intercept: (–2, 0), y–intercept: (0, –1)
B)
x–intercept: (–1, 0), y–intercept: (0, 2)
C)
x–intercept: (–1, 0), y–intercept: (0, –2)
D)
x–intercept: (2, 0), y–intercept: (0, –1)
Identify the quadrant in which the point is located.
45)
(–5.6, –2.2)
45)
A)
Quadrant I
B)
Quadrant IV
C)
Quadrant III
D)
Quadrant II
Solve the problem.
34
46)
An entrepreneur is establishing a small business to manufacture glass lamp shades. Her initial
investment is $5000, and her unit cost to manufacture each lamp shade is $90. Write an equation
that gives the total cost C of manufacturing n lamp shades. Plot the total cost of manufacturing 100,
200, and 300 lamp shades.
46)
A)
C =5000n
B)
C =90n –5000
C)
C =90n +5000
D)
C =90n
35
Graph and shade the given inequality.
47)
x + y < –6
47)
A)
B)
C)
D)
Provide an appropriate response.
48)
What are the slope and the y–intercept of the graph of y =9x –4?
48)
A)
Slope –4; y–intercept (0, 9)
B)
Slope 9; y–intercept (0, 4)
C)
Slope 9; y–intercept (–4, 0)
D)
Slope 9; y–intercept (0, –4)
Graph the line on the coordinate plane using the given information.
36
49)
Passes through (0, 3) and m = – 1
6
49)
A)
B)
C)
D)
37
Graph.
50)
y = 0.3x –7
50)
A)
B)
C)
D)
38
Graph using the slope and the y–intercept.
51)
y = x + 7
51)
A)
B)
C)
D)
Decide if the given ordered pair is a solution to the inequality.
52)
2x + 3y –6: (3, 6)
52)
A)
Yes
B)
No
Solve the problem.
53)
The owner of a shop bought an inventory software program for $350. The value, V, of the software
program declines by $10 per year.
(i) Write an equation for V after t years.
(ii) Graph the equation found in part (i).
(iii) Explain the significance of the two intercepts in this context.
(iv) Use the graph to estimate the value of the software after 3 yr.
53)
39
A)
(i) V =10t +350
(ii)
(iii) The V–intercept is the value of the
software program when it was purchased.
The t–intercept is the number of years from
the year of purchase when the value of the
software will be $0.
(iv) $310 is the value after 3 yr.
B)
(i) V = –10t +350
(ii)
(iii) The V–intercept is the value of the
software program when it was purchased.
The t–intercept is the number of years from
the year of purchase when the value of the
software will be $0.
(iv) $320 is the value after 3 yr.
40
C)
(i) V =10t –350
(ii)
(iii) The V–intercept is the value of the
software program when it was purchased.
The t–intercept is the number of years from
the year of purchase when the value of the
software will be $0.
(iv) $145 is the value after 3 yr.
D)
(i) V = –10t –350
(ii)
(iii) The V–intercept is the value of the
software program when it was purchased.
The t–intercept is the number of years from
the year of purchase when the value of the
software will be $0.
(iv) $330 is the value after 3 yr.
41
Find the equation of the graph.
54)
54)
A)
x =6.5
B)
x = –6.5
C)
y =6.5
D)
y = –6.5
Solve the problem.
55)
The cost, T, in hundreds of dollars, of tuition at one community college is given by T =2+ 1.25c,
where c is the number of credits for which a student registers. Graph the equation and use the
graph to estimate the cost of tuition if a student registers for 8 credits.
55)
A)
$2200
B)
$1200
C)
$1800
D)
$1000
56)
The cost, c, in dollars of renting a motorized scooter is c =6+ 0.25m, where m is the number of
miles driven. Graph the equation and use the graph to estimate the cost, to the nearest dollar, of the
scooter rental if the number of miles driven is 38.
56)
A)
About 21 dollars
B)
About 12 dollars
C)
About 39.5 dollars
D)
About 16 dollars
42
Graph and shade the given inequality.
57)
–2x – 3y 6
57)
A)
B)
C)
D)
Decide if the given ordered pair is a solution to the inequality.
58)
x + 2y > –3: (6, –4)
58)
A)
Yes
B)
No
Write the equation in slope–intercept form.
59)
y – 1 =4(x +6)
59)
A)
y =4x +24
B)
y = x +25
C)
y =4x +25
D)
y =4x +7
Decide if the given ordered pair is a solution to the inequality.
60)
x + 2y >3: (6, 1)
60)
A)
Yes
B)
No
43
Provide an appropriate response.
61)
In the following graph, find the x–intercept and the y–intercept.
61)
A)
x–intercept: (–8, 0), y–intercept: (0, 4)
B)
x–intercept: (4, 0), y–intercept: (0, 8)
C)
x–intercept: (8, 0), y–intercept: (0, 4)
D)
x–intercept: (–4, 0), y–intercept: (0, –8)
Solve the problem.
62)
In a certain state the annual consumption, b, of beef (in kilograms per person) can be estimated by
b = –0.33t +21, where t is the number of years since 2005. Graph the equation and use the graph to
estimate the beef consumption, to the nearest kilogram, in the year 2022.
62)
A)
About 27 kg per person
B)
About 12 kg per person
C)
About 9 kg per person
D)
About 15 kg per person
Find the x– and y–intercepts for the equation. Then graph the equation.
63)
y =1
6x
63)
44
A)
x–intercept: (0, 0), y–intercept: (0, 0)
B)
x–intercept: (0, 0), y–intercept: (0, 0)
C)
x–intercept: (0, 0), y–intercept: (0, 0)
D)
x–intercept: (0, 0), y–intercept: (0, 0)
Graph using the slope and the y–intercept.
64)
y = – 1
5x – 5
64)
45
A)
B)
C)
D)
Provide an appropriate response.
65)
On the coordinate plane shown, plot the points A(1, 6) and B(–2, 0).
65)
46
A)
B)
C)
D)
Solve the problem.
66)
Tickets to a ballet cost $16 if bought in advance. If bought on the date of the ballet, they cost $21.
For the ballet to make a profit, the total money collected from ticket sales must be at least $370.
Write an inequality to represent this situation, using x for the number of tickets bought in advance
and y for the number of tickets bought on the date of the ballet. Graph the equation.
66)
47
A)
16x –21y 370
B)
16x +21y 370
C)
16x +21y 370
D)
16x –21y 370
Provide an appropriate response.
67)
In which quadrant is the point (–3, 11) located?
67)
A)
Quadrant I
B)
Quadrant IV
C)
Quadrant II
D)
Quadrant III
Find the x– and y–intercepts for the equation. Then graph the equation.
68)
3x – y =8
68)
48
A)
x–intercept: (–8, 0) , y–intercept: 0, 8
3
B)
x–intercept: 8
3, 0 , y–intercept: (0, –8)
C)
x–intercept: –8
3, 0 , y–intercept: (0, –8)
D)
x–intercept: 8
3, 0 , y–intercept: (0, –8)
Graph the equation.
69)
x = –1
69)
49
A)
B)
C)
D)
Graph the line containing the given pair of points and find the slope.
70)
(–4, 0) (1, –1)
70)
50
A)
1
5
B)
–5
C)
5
D)
–1
5
Solve the problem.
71)
Suppose that during a certain step in a chemical manufacturing process the amount of chlorine
dissolved in a solution, measured in parts per million (ppm), is related to the elapsed time
measured from the beginning of the step. Use the following table and graph as a representation of
this relationship.
ELAPSED TIME (minutes) 3 6 9 12 15
AMOUNT DISSOLVED (ppm) 24.0 26.4 28.4 30.4 32.2
Is the slope positive, negative, zero, or undefined?
71)
A)
Undefined
B)
Negative
C)
Zero
D)
Positive
51
Provide an appropriate response.
72)
The graph on the following coordinate plane shows how the cost of a taxi ride relates to the number
of minutes that the taxi has been driven.
Is the slope of the graphed line positive, negative, zero, or undefined? Describe in a sentence or two
the relationship between the cost and the number of minutes driven?
72)
A)
The slope is zero. As the number of minutes driven increases, the cost remains the same.
B)
The slope is negative. As the number of minutes driven increases, the cost decreases.
C)
The slope is undefined. You cannot describe the relationship between the cost and the number
of minutes driven.
D)
The slope is positive. As the number of minutes driven increases, the cost increases.
52
Graph using the slope and the y–intercept.
73)
x + y = –4
73)
A)
B)
C)
D)
Graph.
53
74)
y = 0
74)
A)
B)
C)
D)
Provide an appropriate response.
75)
The points (0, 6) and (3, 4) lie on a line. Find its equation.
75)
A)
y = – 2
3x + 6
B)
y =2
3x + 6
C)
y = – 2
3x – 6
D)
y =2
3x – 6
54
Decide if the given ordered pair is a solution to the inequality.
76)
x y + 7: (3, –5)
76)
A)
Yes
B)
No
Find the x– and y–intercepts for the equation. Then graph the equation.
77)
y =6x
77)
A)
x–intercept: (0, 0), y–intercept: (0, 0)
B)
x–intercept: (0, 0), y–intercept: (0, 0)
C)
x–intercept: (0, 0), y–intercept: (0, 0)
D)
x–intercept: (0, 0), y–intercept: (0, 0)
55
Find the equation of the graph.
78)
78)
A)
x = –3.5
B)
y = –3.5
C)
y =3.5
D)
x =3.5
Solve the problem.
79)
The value, v, in hundreds of dollars, of Juan’s television is approximated by v = –0.50t +9, where t
is the number of years since he first bought the television. Graph the equation and use the graph to
estimate the value of the television 2 years after it was purchased.
79)
A)
$800
B)
$1000
C)
$860
D)
$700
56
Complete the ordered pairs. Then graph the equation by plotting the points and drawing a line through them.
80)
y =2x – 4 (0, ), ( , 0), (2, )
80)
A)
(0, –4), (–8, 0), (2, –3)
B)
(0, –4), (–2, 0), (2, –8)
C)
(0, 4), (–2, 0), (2, 8)
D)
(0, –4), (2, 0), (2, 0)
57
Graph using the slope and the y–intercept.
81)
y =5.307x +2.083
81)
A)
B)
C)
D)
58
Find the equation of the graph.
82)
82)
A)
x = –6.5
B)
y =6.5
C)
x =6.5
D)
y = –6.5
59
Graph using the slope and the y–intercept.
83)
y = –5x – 3
83)
A)
B)
C)
D)
60
Find the equation of the graph.
84)
84)
A)
y = –x +6
B)
y = x –6
C)
y = x +6
D)
y = –x –6
Graph the line on the coordinate plane using the given information.
85)
Passes through (0, 2) and m =1
6
85)
A)
B)
61
C)
D)
62
86)
Passes through (–5, 10) and m = 0
86)
A)
B)
C)
D)
Graph.
63
87)
y =1
5x + 6
87)
A)
B)
C)
D)
64
Graph and shade the given inequality.
88)
x – y > –5
88)
A)
B)
C)
D)
65
Find the coordinates of the labeled points.
89)
89)
A)
A(–5, 0); B(–2, –2)
B)
A(–5, 0); B(2, –2)
C)
A(–5, 5); B(2, –2)
D)
A(5, 0); B(2, –2)
Find an equation in slope–intercept form of the line satisfying the specified conditions.
90)
A horizontal line that passes through the point (–9, 7)
90)
A)
x =7
B)
x = –9
C)
y =7
D)
y = –9
Graph.
91)
x =2
91)
A)
B)
66
C)
D)
On the coordinate plane below, plot the points with the given coordinates.
92)
A(2, 5), B(–6, –3)
92)
A)
B)
67
C)
D)
Complete the ordered pairs. Then graph the equation by plotting the points and drawing a line through them.
93)
y = x – 3 (0, ), ( , 0), (3, )
93)
A)
(0, 3), (3, 0), (3, 0)
B)
(0, –3), (3, 0), (3, 0)
C)
(0, 3), (–3, 0), (3, 6)
D)
(0, –3), (–3, 0), (3, –6)
68
Find an equation in slope–intercept form of the line satisfying the specified conditions.
94)
Through the origin and the point (1, 5)
94)
A)
y =5
B)
y =1
C)
y = x
D)
y =5x
Solve the problem.
95)
Suppose the sales of a particular brand of appliance satisfy the relationship y =250x + 5000, where
y represents the number of sales in year x, with x = 0 corresponding to 1995. Find the number of
sales in 2010.
95)
A)
8500 sales
B)
17,250 sales
C)
17,500 sales
D)
8750 sales
96)
Jason bought x rose plants and y sunflower plants for his garden. Rose plants cost $7 each, and
sunflower plants cost $15 each. If his spending limit was $264., write an inequality to show the
possible combinations of rose plants and sunflower plants he could have bought. Graph the
equation.
96)
A)
7x +15y 264
B)
15x +7y 264
C)
15x +7y 264
D)
7x +15y 264
69
Graph and shade the given inequality.
97)
y < –4
97)
A)
B)
C)
D)
Solve the problem.
98)
A hardware store owner advertises a certain brand of drill. Each month he changes the price of the
drill and tracks the number of units sold. After six months of tracking, he derives an equation
equating the price and the number of units sold. His equation is sales (s) equals –3 times the price
(p) plus the constant 32, or s = –3p +32. Complete the table, plot the points on the graph, and use
the information to predict how many units will be sold if the price is $10 each.
98)
70
P S
6
7
8
9
10
A)
P S
614
711
8 8
9 5
10 2
14 units will be sold if the price is $10 each.
B)
P S
650
753
856
959
10 62
50 units will be sold if the price is $10 each.
C)
P S
650
753
856
959
10 62
62 units will be sold if the price is $10 each.
71
D)
P S
614
711
8 8
9 5
10 2
2 units will be sold if the price is $10 each.
Graph the equation.
99)
5x +3y =15
99)
A)
B)
C)
D)
72
Find the equation of the graph.
100)
100)
A)
y =2
B)
x =2
C)
x = –2
D)
y = –2
Decide if the given ordered pair is a solution to the inequality.
101)
x – y 3: (3, –2)
101)
A)
Yes
B)
No
Graph the line containing the given pair of points and find the slope.
102)
(1, 8) (0, 0)
102)
A)
–1
8
B)
–8
73
C)
1
8
D)
8
Identify the quadrant in which the point is located.
103)
7
15, –1
2
103)
A)
Quadrant III
B)
Quadrant I
C)
Quadrant II
D)
Quadrant IV
Find the coordinates of the labeled points.
104)
104)
A)
A(1, –1); B(1, –3)
B)
A(–1, 1); B(0, 3)
C)
A(1, 1); B(0, –3)
D)
A(1, 1); B(0, 3)
Decide if the given ordered pair is a solution to the inequality.
105)
x + 2y < –6: (0, 0)
105)
A)
Yes
B)
No
74
Solve the problem.
106)
Tickets to a ballet cost $12 if bought in advance. If bought on the date of the ballet, they cost $25.
For the ballet to make a profit, the total money collected from ticket sales must be at least $370.
Write an inequality to represent this situation, using x for the number of tickets bought in advance
and y for the number of tickets bought on the date of the ballet. Graph the equation.
106)
A)
12x –25y 370
B)
12x +25y 370
C)
12x –25y 370
D)
12x +25y 370
107)
Alison sets aside $45 each month to spend on books and music files. If she spends m dollars on
music files in a given month she may spend b dollars on books where m + b =45. Graph the
equation and use the graph to estimate the amount Alison may spend on books in March if she
spends $31 on music files.
107)
A)
$25
B)
$21
C)
$76
D)
$14
75
108)
Suppose that the speed of a car, measured in miles per hour (mph), is monitored for some short
period of time after the driver applies the brakes. The following table and graph relate the speed of
the car to the amount of time, measured in seconds (sec), elapsed from the moment that the brakes
are applied.
ELAPSED TIME (sec) 3 6 9 12 15
SPEED of CAR (mph) 46 31 21 11 6
Is the slope of the graph positive or negative and is the slope constant, or does it change over time?
108)
A)
Positive, changes over time
B)
Negative, constant
C)
Negative, changes over time
D)
Positive, constant
Complete the table for the equation.
109)
y + x =7
x y
2
7
0
109)
A)
x y
210
7 0
0 7
B)
x y
2 5
7–3
0 7
C)
x y
2 2
7 7
0 0
D)
x y
2 5
7 0
0 7
76
Find the coordinates of the labeled points.
110)
110)
A)
C(4, 6); D(–5, 5)
B)
C(–5, –5); D(4, –5)
C)
C(–5, 4); D(–5, 5)
D)
C(–5, 4); D(5, –5)
77
Graph using the slope and the y–intercept.
111)
y =5x + 4
111)
A)
B)
C)
D)
Find the x– and y–intercepts for the equation. Then graph the equation.
78
112)
y = – 1
2x +3
112)
A)
x–intercept: (6, 0), y–intercept: (0, 3)
B)
x–intercept: (6, 0), y–intercept: (0, –6)
C)
x–intercept: (–6, 0), y–intercept: (0, 3)
D)
x–intercept: (–3, 0), y–intercept: (0, 3)
Decide if the given ordered pair is a solution to the inequality.
113)
2x + 3y < 5: 1
2, 1
2
113)
A)
Yes
B)
No
On the coordinate plane below, plot the points with the given coordinates.
79
114)
A(4, 6), B(1, –3)
114)
A)
B)
C)
D)
80
Graph and shade the given inequality.
115)
x + 3y 4
115)
A)
B)
C)
D)
Find the slope and the y–intercept of the line.
116)
y = –8x –2
116)
A)
Slope –2; y–intercept (0, –8)
B)
Slope –8; y–intercept (–2, 0)
C)
Slope –8; y–intercept (0, 2)
D)
Slope –8; y–intercept (0, –2)
Provide an appropriate response.
117)
Find the equation of the line with slope –4 that passes through point (0, –3).
117)
A)
y = –4x +3
B)
y = –4x –3
C)
y =4x –3
D)
y =4x +3
81
Find an equation in slope–intercept form of the line satisfying the specified conditions.
118)
Through (1, –9), perpendicular to 9x – 7y = –54
118)
A)
y = – 9
7x –9
7
B)
y = – 7
9x –74
9
C)
y = – 1
7x –54
7
D)
y =7
9x –74
9
Decide if the given ordered pair is a solution to the inequality.
119)
x + y >7: (1, 9)
119)
A)
Yes
B)
No
Solve the problem.
120)
The graph shows Big D sales, in thousands of dollars, for two consecutive years. Which month in
Year 2 had the highest sales?
Big D Sales
Year 2
Year 1
Month
120)
A)
Month 7
B)
Month 12
C)
Month 2
D)
Month 6
82
Graph and shade the given inequality.
121)
y 5x
121)
A)
B)
C)
D)
Graph the line containing the given pair of points and find the slope.
83
122)
(2, –6) (–1, 3)
122)
A)
–1
3
B)
– 3
C)
1
3
D)
3
84
Provide an appropriate response.
123)
Are the graphs of y =5x + 7 and y =5x – 4 parallel? Explain how you know.
123)
A)
The graphs are parallel. The slope of y =5x + 7 is 7 and the slope of y =5x – 4 is –4. Since the
slopes of the two lines are not equal, their graphs are parallel.
B)
The graphs are not parallel. The slope of y =5x + 7 is 5 and the slope of y =5x – 4 is also 5.
Since the slopes of the two lines are equal, their graphs are not parallel.
C)
The graphs are parallel. The slope of y =5x + 7 is 5 and the slope of y =5x – 4 is also 5. Since
the slopes of the two lines are equal, their graphs are parallel.
D)
The graphs are not parallel. The slope of y =5x + 7 is 7 and the slope of y =5x – 4 is –4. Since
the slopes of the two lines are not equal, their graphs are not parallel.
Solve the problem.
124)
The cost of manufacturing a molded part is related to the quantity produced during a production
run. When 100 parts are produced, the cost is $300. When 500 parts are produced, the cost is $1500.
Write a linear equation in point–slope form that gives the relationship between the number of parts
produced and the cost of manufacturing.
124)
A)
y – 300 =3.00(x – 100) or y –1500 =3.00(x –500)
B)
y – 300 =2.40(x – 100) or y –1500 =2.40(x –500)
C)
y – 300 =0.33(x – 100) or y –1500 =0.33(x –500)
D)
y – 300 =4.00(x – 100) or y –1500 =4.00(x –500)
125)
A moving firm charges a flat fee of $35 plus $30 per hour. Let y be the cost in dollars of using the
moving firm for x hours. Find the slope–intercept form of the equation.
125)
A)
y =35x – 30
B)
y =30x + 35
C)
y =30x – 35
D)
y =35x + 30
Decide whether the slope is positive, negative, zero, or undefined.
126)
126)
A)
Negative
B)
Zero
C)
Undefined
D)
Positive
Solve the problem.
85
127)
In order to make a profit an automobile dealer must sell at least 150 vehicles a month. The dealer
plans to sell x units of one model and y units of another model. This situation can be modeled by
the inequality x + y 150.Graph this inequality in Quadrant I.
127)
A)
B)
C)
D)
Graph using the slope and the y–intercept.
86
128)
y = – 1
4x
128)
A)
B)
C)
D)
87
Complete the ordered pairs. Then graph the equation by plotting the points and drawing a line through them.
129)
x + y = –2 (0, ), ( , 0), (5, )
129)
A)
(0, 2), (–2, 0), (5, 7)
B)
(0, 2), (2, 0), (5, –3)
C)
(0, –2), (–2, 0), (5, –7)
D)
(0, –2), (2, 0), (5, 3)
88
Graph using the slope and the y–intercept.
130)
y = –0.359x –2.779
130)
A)
B)
C)
D)
89
131)
2x – y = –4
131)
A)
B)
C)
D)
90
Solve the problem.
132)
The graph depicts a relationship between scores achieved on an unspecified standardized test and
family income. Find the slope of the line.
Score
r
Income (in $1000’s)
132)
A)
150 points per thousand dollars
B)
1.5 point(s) per thousand dollars
C)
1500 points per thousand dollars
D)
15.1 points per thousand dollars
Find the equation of the graph.
133)
133)
A)
y =3x – 6
B)
y = –2x – 6
C)
y =2x – 6
D)
y =1
3x + 2
Decide if the given ordered pair is a solution to the inequality.
134)
y –x: (10, –10)
134)
A)
Yes
B)
No
Write the equation in slope–intercept form.
135)
x –9y =4
135)
A)
y =9x – 4
B)
y = x –4
9
C)
y =1
9x –4
9
D)
y =1
9x – 4
91
Provide an appropriate response.
136)
For the equation y + 3x = –4, complete the following table.
x–4 0
y0 8
136)
A)
x–4 0 –4
38
y8 8 0 8
B)
x–4 0 –4
30
y8–4 0 8
C)
x–4 0 –4
3–4
y–4–4 0 8
D)
x–4 0 –4
3–4
y8–4 0 8
Find the slope and the y–intercept of the line.
137)
6x + 7y =52
137)
A)
Slope 11
6; y–intercept 0, 7
52
B)
Slope 6
7; y–intercept 0, 52
7
C)
Slope –6
7; y–intercept 0, 52
7
D)
Slope –11
6; y–intercept 0, 7
52
Find an equation in slope–intercept form of the line satisfying the specified conditions.
138)
Passing through the points (0, –8) and (8, –2)
138)
A)
y = – 3
4x – 8
B)
y = – 3
4x + 8
C)
y =3
4x + 8
D)
y =3
4x – 8
Given points P, Q, R, and S, determine whether linesPQ and RSare perpendicular, parallel, or neither.
139)
P(1, 5), Q(5, 13), R(8, 19), S(40, 83)
139)
A)
Parallel
B)
Neither
C)
Perpendicular
Graph.
140)
y =5
6x + 1
140)
92
A)
B)
C)
D)
Provide an appropriate response.
141)
Write the equation 6x – y = –4 in slope–intercept form.
141)
A)
y = –6x –4
B)
y =6x –4
C)
y =6x +4
D)
y = –6x +4
93
Graph the line on the coordinate plane using the given information.
142)
Passes through (0, 4) and m = – 2
142)
A)
B)
C)
D)
Graph the line containing the given pair of points and find the slope.
94
143)
(3, 8) (–4, 8)
143)
A)
0
B)
1
C)
1
D)
0
95
Solve the problem.
144)
The graph records the amount of inventory on hand for two items, A and B.
For the period of time when both items were tracked, was the rate of change in product A the same
as for product B? Why or why not?
144)
A)
No, the slopes of the two lines are equal.
B)
Yes, the slopes of the two lines are not equal.
C)
Yes, the slopes of the two lines are equal.
D)
No, the lengths of the two lines are not equal.
Graph.
145)
x = 0
145)
96
A)
B)
C)
D)
Find the equation of the graph.
146)
146)
A)
y = –6x – 4
B)
y =2
3x – 4
C)
y =3
2x + 6
D)
y =6x – 4
97
Solve the problem.
147)
The graph depicts a relationship between scores achieved on an unspecified standardized test and
family income. Find the slope of the line.
Income (in $1000’s)
147)
A)
4
3 points per thousand dollars
B)
20
3 points per thousand dollars
C)
20 points per thousand dollars
D)
4 points per thousand dollars
148)
During the month of January, the depth, d, of snow in inches at the base of one ski resort could be
approximated by d = –2t +64, where t is the number of days since December 31st. Graph the
equation and use the graph to estimate the depth of snow on January 27th.
148)
A)
18 in.
B)
37 in.
C)
10 in.
D)
15 in.
98
Graph using the slope and the y–intercept.
149)
–5x + 40y = –35
149)
A)
B)
C)
D)
Find the slope and the y–intercept of the line.
150)
–2x + 6y =24
150)
A)
Slope 3; y–intercept (0, –4)
B)
Slope –1
3; y–intercept (0, –4)
C)
Slope –3; y–intercept (0, 4)
D)
Slope 1
3; y–intercept (0, 4)
99
Graph and shade the given inequality.
151)
y < –5x + 1
151)
A)
B)
C)
D)
Find the x– and y–intercepts for the equation. Then graph the equation.
100
152)
x +2y =8
152)
A)
x–intercept: (–8, 0), y–intercept: (0, –8)
B)
x–intercept: (4, 0), y–intercept: (0, 8)
C)
x–intercept: (8, 0), y–intercept: (0, 4)
D)
x–intercept: (8, 0), y–intercept: (0, 8)
Find an equation in slope–intercept form of the line satisfying the specified conditions.
153)
Passing through the points (–3, 10) and (10, –3)
153)
A)
y = x – 7
B)
y = x + 7
C)
y = –x + 7
D)
y = –x – 7
Graph.
101
154)
y =6
154)
A)
B)
C)
D)
102
Solve the problem.
155)
Suppose y = mx + b is a mathematical model for actual time as a function of estimated time, where
y represents actual time and x represents estimated time and m and b are constants. If m =0.9 and
b = –1.3, find y when x is 30 min.
155)
A)
28.3 min
B)
28.83 min
C)
31.17 min
D)
25.7 min
On the coordinate plane below, plot the points with the given coordinates.
156)
A(–2
3, –6), B(–4, 1)
156)
A)
B)
103
C)
D)
104
Graph the linear inequality.
157)
y < –5x + 1
157)
A)
B)
C)
D)
105
Decide whether the slope is positive, negative, zero, or undefined.
158)
158)
A)
Undefined
B)
Positive
C)
Negative
D)
Zero
106
Graph the line on the coordinate plane using the given information.
159)
Passes through (5, –2) and m = 0
159)
A)
B)
C)
D)
107
160)
Passes through (10, 0) and m = – 1
2
160)
A)
B)
C)
D)
On the coordinate plane below, plot the points with the given coordinates.
108
161)
A(2, 0), B (0, –4)
161)
A)
B)
C)
D)
109
Complete the ordered pairs. Then graph the equation by plotting the points and drawing a line through them.
162)
4x – y =4(0, ), ( , 0), (4, )
162)
A)
(0, 4), (–1, 0), (4, 20)
B)
(0, –4), (–1, 0), (4, –20)
C)
(0, –4), (–16, 0), (4, –3)
D)
(0, –4), (1, 0), (4, 12)
Identify the quadrant in which the point is located.
163)
(12, –7)
163)
A)
Quadrant II
B)
Quadrant I
C)
Quadrant III
D)
Quadrant IV
Graph.
110
164)
y = – 21
2
164)
A)
B)
C)
D)
Write the equation in slope–intercept form.
165)
4x – 7y =7
165)
A)
y =4x – 7
B)
y =4
7x +1
C)
y =7
4x +7
4
D)
y =4
7x –1
On the coordinate plane below, plot the points with the given coordinates.
111
166)
A(0, 3), B (–2, 0)
166)
A)
B)
C)
D)
112
Solve the problem.
167)
A hiker is at point A as shown in the graph and wants to take the shortest route through a field to
reach a nearby road represented by BC. The shortest route will be to walk perpendicular to the
road. Is AD the shortest route? Explain.
167)
A)
The product of the slopes of the two lines is 1
6· – 6 , which is equal to –1, so AD is
perpendicular to BC and is therefore the shortest route.
B)
The product of the slopes of the two lines is 1
6·6, which is equal to 1, so AD is not
perpendicular to BC and is therefore not the shortest route.
C)
The product of the slopes of the two lines is 1
6·6, which is equal to 1, so AD is perpendicular
to BC and is therefore the shortest route.
D)
The product of the slopes of the two lines is 1
6· – 6 , which is equal to –1, so AD is not
perpendicular to BC and is therefore not the shortest route.
113
168)
Suppose that the speed of a car, measured in miles per hour (mph), is monitored for some short
period of time after the driver applies the brakes. The following coordinate plane displays the
relationship between the speed of the car to the amount of time, measured in seconds (sec), elapsed
from the moment that the brakes are applied. Estimate the coordinates of the plotted points. What
general trend do the data reflect?
168)
A)
A(48, 2), B(33, 4), C(23, 6), D(13, 8), and E(8, 10); With increasing elapsed time, the speed
increases.
B)
A(2, 48), B(4, 33), C(6, 23), D(8, 13), and E(10, 8); With increasing elapsed time, the speed
decreases.
C)
A(48, 2), B(33, 4), C(23, 6), D(13, 8), and E(8, 10); With increasing elapsed time, the speed
decreases.
D)
A(2, 48), B(4, 33), C(6, 23), D(8, 13), and E(10, 8); With increasing elapsed time, the speed
increases.
Graph the equation.
169)
y =1
169)
114
A)
B)
C)
D)
Find the coordinates of the labeled points.
170)
170)
A)
G(5, –7); H(–7, –7)
B)
G(–7, 26); H(–7, –4)
C)
G(5, –7); H(–4, –7)
D)
G(5, –7); H(–7, –4)
Write the equation in slope–intercept form.
171)
20x + 2y =10
171)
A)
y = – 10x +5
B)
y =10x –5
C)
y =10x +5
D)
y =20x – 10
115
Complete the table for the equation.
172)
y + 4x =21
x y
5
21
0
172)
A)
x y
5 1
21 –63
0–63
B)
x y
521
21 –63
0–63
C)
x y
5 1
21 –63
021
D)
x y
521
21 21
021
Solve the problem.
173)
Suppose that during a certain step in a chemical manufacturing process the amount of
hydrogen sulfide dissolved in a solution, measured in parts per million (ppm), is related to the
elapsed time measured from the beginning of the step. Use the following table as a representation
of this relationship. What does the ordered pair (9, 20.4) mean in the context of this situation?
TIME
(minutes) AMOUNT DISSOLVED
(ppm)
316.0
618.4
920.4
12 22.4
15 24.2
173)
A)
(9, 20.4) indicates that 20.4 ppm of hydrogen sulfide was dissolved after 9 minutes elapsed.
B)
(9, 20.4) indicates that 20.4 ppm of hydrogen sulfide was dissolved after 15 minutes elapsed.
C)
(9, 20.4) indicates that 20.4 ppm of hydrogen sulfide was dissolved after 9 seconds elapsed.
D)
(9, 20.4) indicates that 9 ppm of hydrogen sulfide was dissolved after 20.4 minutes elapsed.
Graph the line on the coordinate plane using the given information.
174)
Passes through (0, 6) and m = – 1
5
174)
116
A)
B)
C)
D)
Solve the problem.
175)
If a car travels at a constant speed, which graph best represents the distance the car has traveled?
175)
A)
Graph B
B)
Graph C
C)
Graph A
D)
Graph D
117
Graph the line on the coordinate plane using the given information.
176)
Passes through (1, 9) and the slope is undefined
176)
A)
B)
C)
D)
Identify the quadrant in which the point is located.
177)
(16, 2)
177)
A)
Quadrant II
B)
Quadrant IV
C)
Quadrant III
D)
Quadrant I
118
Provide an appropriate response.
178)
For the points P(1, 5), Q(4, 8), R(3, 1) and S(12, –8), indicate whether PQ is perpendicular to RS.
Explain.
178)
A)
The product of the slopes of the lines is 1, therefore PQ is not perpendicular to RS.
B)
The slopes of the lines are the same, therefore PQ is not perpendicular to RS.
C)
The slopes of the lines are the same, therefore PQ is perpendicular to RS.
D)
The product of the slopes of the lines is –1, therefore PQ is perpendicular to RS.
Find the equation of the graph.
179)
179)
A)
y = x –6
B)
y = –x –6
C)
y = x +6
D)
y = –x +6
Given points P, Q, R, and S, determine whether linesPQ and RSare perpendicular, parallel, or neither.
180)
P(1, 7), Q(2, 10), R(9, 1), S(18, –2)
180)
A)
Perpendicular
B)
Neither
C)
Parallel
Identify the quadrant in which the point is located.
181)
(–18, –10)
181)
A)
Quadrant II
B)
Quadrant III
C)
Quadrant IV
D)
Quadrant I
Solve the problem.
182)
When force is applied to a spring, its length changes. The length L and the force F are related by a
linear equation. A certain spring is initially 18 inches long when no force is applied. When 9
pounds of force is applied, the length becomes 22 inches. What is the equation that relates length
and force?
182)
A)
L = – 4
9F –18
B)
L =9
4F –18
C)
L = – 9
4F +18
D)
L =4
9F +18
Find an equation in slope–intercept form of the line satisfying the specified conditions.
183)
Through (1, 9), parallel to 9x – 7y = –33
183)
A)
y =7
9x + 1
B)
y =33
7x +33
7
C)
y =9
7x +54
7
D)
y = – 9
7x –54
7
Find the x– and y–intercepts for the equation. Then graph the equation.
119
184)
16y – 4x = –8
184)
A)
x–intercept: (2, 0), y–intercept: 0, –1
2
B)
x–intercept: (–2, 0), y–intercept: 0, 1
2
C)
x–intercept: (–2, 0), y–intercept: 0, –1
2
D)
x–intercept: 0, –1
2, y–intercept: (–2, 0)
Find an equation in slope–intercept form of the line satisfying the specified conditions.
185)
A vertical line that passes through the point (1, –4)
185)
A)
y =1
B)
x =1
C)
y = –4
D)
x = –4
120
Graph using the slope and the y–intercept.
186)
y =4x – 3
186)
A)
B)
C)
D)
121
Complete the table for the equation.
187)
y + x = –4
x y
–3
–4
0
187)
A)
x y
–3–5
–4 0
0–4
B)
x y
–3–5
–4–1
0–4
C)
x y
–3–1
–4 0
0–4
D)
x y
–3–1
–4 0
0 0
Solve the problem.
188)
Suppose that during a certain step in a chemical manufacturing process the amount of
hydrogen sulfide dissolved in a solution, measured in parts per million (ppm), is related to the
elapsed time measured from the beginning of the step. Use the following table as a representation
of this relationship.
ELAPSED TIME (minutes) 3 6 9 12 15
AMOUNT DISSOLVED (ppm) 16.0 18.4 20.4 22.4 24.2
Plot the information on the following coordinate plane. What general trend do the data reflect?
188)
A)
With increasing elapsed time, the
amount of dissolved hydrogen sulfide increases.
122
B)
With increasing elapsed time, the
amount of dissolved hydrogen sulfide increases.
C)
With increasing elapsed time, the
amount of dissolved hydrogen sulfide decreases.
D)
With increasing elapsed time, the
amount of dissolved hydrogen sulfide decreases.
Find an equation in slope–intercept form of the line satisfying the specified conditions.
189)
Through (–4, 17), perpendicular to –7x + 2y =44
189)
A)
y = – 2
7x +111
7
B)
y =2
7x –44
7
C)
y =2
7x –111
7
D)
y = – 7
2x –111
2
123
Find the equation of the graph.
190)
190)
A)
y = –6
B)
y =6
C)
x = –6
D)
x =6
124
Graph and shade the given inequality.
191)
x 3
191)
A)
B)
C)
D)
Solve the problem.
192)
The position of a dropped object for various times after the object is released is given in the
following table.
Point Time After Release
(in seconds) Position (in feet)
A 2 –64
B 3 –144
C 4 –256
192)
125
(i) Compute the slopes of AB and BC by graphing.
(ii) Was the rate of fall for the dropped object constant throughout the experiment? Explain.
A)
(i) AB: m = –40 and BC: m = –40
(ii) The slopes of the two lines are equal; therefore the rate of fall was constant throughout the
experiment.
B)
(i) AB: m = –80 and BC: m = –112
(ii) The slopes of the two lines are not equal; therefore the rate of fall was not constant
throughout the experiment.
C)
(i) AB: m = – 1
40 and BC: m = – 1
40
(ii) The slopes of the two lines are equal; therefore the rate of fall was constant throughout the
experiment.
D)
(i) AB: m = – 1
80 and BC: m = – 1
112
(ii) The slopes of the two lines are not equal; therefore the rate of fall was not constant
throughout the experiment.
126
193)
The following graph shows data for a recent train ride from New York to Toronto.
(i) Find the slope of the line.
(ii) Find the equation of the line in slope–intercept form.
(iii) Explain the significance of the y–intercept in this situation.
Time of Day (PM)
193)
A)
(i) 40, or, 40 miles per hour
(ii) y =40x
(iii) The y–intercept is (0,0). From the graph, this means that at 12:00 PM (noon), the train is 0
miles from New York (it hasn’t left the station).
B)
(i) 55, or, 55 miles per hour
(ii) y =55x
(iii) The y–intercept is (1,100). From the graph, this means that at 1:00 PM, the train is 100
miles from New York.
C)
(i) 50, or, 50 miles per hour
(ii) y =50x
(iii) The y–intercept is (0,0). From the graph, this means that at 12:00 PM (noon), the train is 0
miles from New York (it hasn’t left the station).
D)
(i) 100, or, 100 miles per hour
(ii) y =100x
(iii) The y–intercept is (1,100). From the graph, this means that at 1:00 PM, the train is 100
miles from New York.
127
Find the x– and y–intercepts for the equation. Then graph the equation.
194)
2x – 6y =6
194)
A)
x–intercept: (–3, 0), y–intercept: (0, –1)
B)
x–intercept: (–3, 0), y–intercept: (0, –1)
C)
x–intercept: (3, 0), y–intercept: (0, –1)
D)
x–intercept: (–3, 0), y–intercept: (0, –1)
Find the slope and the y–intercept of the line.
195)
–6x + 8y =8
195)
A)
Slope –3
4; y–intercept (0, –1)
B)
Slope 3
4; y–intercept (0, 1)
C)
Slope –11
3; y–intercept (0, 1)
D)
Slope 11
3; y–intercept (0, –1)
128
Decide whether the slope is positive, negative, zero, or undefined.
196)
196)
A)
Positive
B)
Negative
C)
Zero
D)
Undefined
Provide an appropriate response.
197)
Do the points (0, 0), (1, –7) and (–1, 7) line on the same line? Explain.
197)
A)
No, the points do not lie on the same line. The line containing (0, 0) and (1, –7) is y =7x. The
line containing (0, 0) and (–1, 7) is y = –7x.
B)
Yes, the points do lie on the same line. The line containing (0, 0) and (1, –7) is y =7x. The line
containing (0, 0) and (–1, 7) is also y =7x.
C)
No, the points do not lie on the same line. The line containing (0, 0) and (1, –7) is y = –7x. The
line containing (0, 0) and (–1, 7) is y =7x.
D)
Yes, the points do lie on the same line. The line containing (0, 0) and (1, –7) is y = –7x. The line
containing (0, 0) and (–1, 7) is also y = –7x.
Complete the table for the equation.
198)
8x + y = –68
x y
–9
0–76
198)
A)
x y
–9 4
0–76
1–76
B)
x y
–9–9
0–68
1–76
C)
x y
–9 4
0 0
1–76
D)
x y
–9 4
0–68
1–76
129
Find the equation of the graph.
199)
199)
A)
y = – 1
2x – 2
B)
y = –4x – 2
C)
y = – 2x – 4
D)
y =4x – 2
Find an equation in slope–intercept form of the line satisfying the specified conditions.
200)
Through (4, –15), parallel to –7x + 9y = –109
200)
A)
y =7
9x –163
9
B)
y = – 109
9x –109
9
C)
y = – 7
9x +163
9
D)
y =9
7x +15
7
Provide an appropriate response.
201)
Given the two points C(–4, –5) and D(–8, 1), compute the slope of the line that passes through the
points.
201)
A)
m = 0
B)
m = – 3
2
C)
m = – 2
9
D)
m = – 9
2
Solve the problem.
202)
A hardware store has room for 900 bags of fertilizer. The fertilizer manufacturer plans to ship x
bags of fertilizer with weed killer and y bags of fertilizer without weed killer. This can be
represented by x + y 900. Graph the inequality.
202)
130
A)
B)
C)
D)
131
Answer Key
Testname: C3
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Answer Key
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Answer Key
Testname: C3
Answer Key
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Answer Key
Testname: C3
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