Unlock access to all the studying documents.
View Full Document
Exam
Name___________________________________
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
One characteristic of a voltage follower is its ________.
If an op–amp’s output increases 8 V every 12 µs in response to a step input voltage, the slew rate
equals ________.
The circuit in Figure 18–1(c) is known as the ________.
voltage follower amplifier
VRF equals ________ in Figure 18–1(c).
A diff–amp with two out–of–phase signal voltages applied to the two inputs is called:
If Rf= 1.2 M and AV= 120 in Figure 18–1(c), Ri equals ________.
The op–amp configuration with the highest possible input impedance is:
C
If Rf= 150 k and Ri= 2.2 k in Figure 18–1(c), the voltage gain equals ________.
Which of these amplifiers provides a high input resistance and a variable gain?
non–inverting amp with a rheostat as Rf.
The feedback attenuation of a voltage follower op–amp is:
C
If Rf= 1.2 M and Ri= 47 k in Figure 18–1(b), the voltage gain equals ________.
If Rf= 0.5 M and Ri= 10 k in Figure 18–1(b), the voltage gain equals ________.
To build an amplifier with a 10 K input impedance and a voltage gain of 41, use the ________
amplifier, Ri= ________, Rf= ________.
non–inverting, 40 k, 200 k
non–inverting, 10 k, 410 k
The input impedance of the amplifier in Figure 18–1(b) is ________.
The distinguishing characteristic of the voltage follower configuration is:
very high input impedance.
What trouble in the amplifier in Figure 18–1(c) could cause the output voltage to clip severely?
The input signal is too large.
The amplifier’s gain is too low.
The input signal is too small for the amplifier to respond.
Identify the open–loop amplifier in Figure 18–1.
Identify the non–inverting amplifier in Figure 18–1.
If you know an op–amp’s open–loop gain only, you can determine the closed–loop gain of:
a voltage follower op–amp.
A practical differential amplifier provides:
very high input impedance.
very high differential voltage gain > 1000.
very small common mode gain < 1.
Which one of these op–amp terminals provides an output that is in–phase with the input?
Which one of these devices produces amplifiers with characteristics close to those of an ideal
amplifier?
If Ri= 2.2 k, Rf= 220 k and AOL = 25,000 in an inverting op–amp, ACL equals ________.
If Rf= 470 k and Ri= 5 k in Figure 18–1(b), the voltage gain equals ________.
A typical op–amp has ________ input impedance and ________ output impedance.
A CMRR of 10,000 means that the op–amp provides that:
the differential input is greatly amplified.
the common mode input is greatly reduced.
What trouble in the amplifier in Figure 18–1(b) could cause the voltage between the inverting and
non–inverting inputs to nearly equal 0 V?
There is no problem; 0 V is normal.
If Ri= 4.7 k and Rf= 0.18 M in Figure 18–1(c), the voltage gain equals ________.
What trouble in the amplifier in Figure 18–1(c) could cause the voltage gain to drop to 1?
If Rf= 100 k and AV= (–833) in Figure 18–1(c), Ri equals ________.
A CMRR of 90,000 equals a decibel CMRR of ________.
If Rf= 5 k and Ri= 10 k in Figure 18–1(c), the voltage gain equals ________.
Which one of these characteristics do an op–amp and a MOSFET have in common?
If Ri= 1 k, Rf= 100 k and VOUT = 5 V in a noninverting op–amp, VRI equals ________.
If Ri= 1 k, Rf= 100 k and VOUT = 5 V in a noninverting op–amp, ACL equals ________.
If Rf= 333 k and Ri= 22 k in Figure 18–1(b), the voltage gain equals ________.
If an op–amp’s output increases 6 V every 18 µs in response to a step input voltage, the slew rate
equals ________.
If Rf= 100 k and Ri= 6.8 k in Figure 18–1(c), the voltage gain equals ________.
To use an op–amp as a buffer, use the ________.
voltage follower amplifier
A diff–amp with 1 input grounded and the signal voltage applied only to the other input is called:
To build an amplifier with a 5 K input impedance and a voltage gain of 40, use the ________
amplifier, Ri= ________, Rf= ________.
non–inverting, 40 k, 200 k
non–inverting, 5 k, 40 k
What is the voltage gain of the amplifier in Figure 18–1(a)?
Which of the amplifiers in Figure 18–1 would be used as a buffer amplifier?
The circuit in Figure 18–1(a) is used as a(n) ________.
One characteristic of a noninverting amplifier is a ________.
voltage gain slightly more than an inverting amplifier with the same values
A
If Rf= 150 k and Ri= 10 k in Figure 18–1(c), the voltage gain equals ________.
A CMRR of 35,000 equals a decibel CMRR of ________.
A diff–amp with two identical signal voltage applied to the two inputs is called:
TRUE/FALSE. Write ‘T’ if the statement is true and ‘F’ if the statement is false.
Differential amplifiers provide high voltage gain and low common–mode rejection.
A typical value of input bias current for an op–amp is around 80 nA.
An op–amp’s CMRR is usually expressed in dB.
The ideal amplifier has infinite gain, infinite input impedance, and zero output impedance.
Practical op–amps come reasonably close to the requirements for an ideal amplifier.
A voltage–follower op–amp has a voltage gain greater than one.
The slew rate of an op–amp is determined by the frequency response of the internal amplifiers.
The open–loop voltage gain of an op–amp is very large.
An op–amp with a low CMRR easily rejects noise signals that appear at both inputs.
An op–amp’s input offset voltage, VOS, is the differential input voltage required to make the
differential output voltage zero.