12) Constructa99%confidenceintervalforthepopulationmean,μ.Assumethepopulationhasanormal
distribution.Agroupof19randomlyselectedemployeeshasameanageof22.4yearswithastandard
deviationof3.8years.Roundtothenearesttenth.
A) (19.9,24.9) B) (16.3,26.9) C) (17.2,23.6) D) (18.7,24.1)
13) Constructa98%confidenceintervalforthepopulationmean,μ.Assumethepopulationhasanormal
distribution.Astudyof14carownersshowedthattheiraveragerepairbillwas$192withastandarddeviation
of$8.Roundtothenearestcent.
A) ($186.33,$197.67) B) ($222.33,$256.10) C) ($328.33,$386.99) D) ($115.40,$158.80)
14) Constructa90%confidenceintervalforthepopulationmean,μ.Assumethepopulationhasanormal
distribution.Inarecentstudyof22eighthgraders,themeannumberofhoursperweekthattheyplayedvideo
gameswas19.6withastandarddeviationof5.8hours.Roundtothenearesthundredth.
A) (17.47,21.73) B) (18.63,20.89) C) (5.87,7.98) D) (19.62,23.12)
15) Arandomsampleof10parkingmetersinaresortcommunityshowedthefollowingincomesforaday.
Assumetheincomesarenormallydistributed.Findthe95%confidenceintervalforthetruemean.Roundto
thenearestcent.
$3.60$4.50$2.80$6.30$2.60$5.20$6.75$4.25$8.00$3.00
A) ($3.39,$6.01) B) ($2.11,$5.34) C) ($4.81,$6.31) D) ($1.35,$2.85)
16) Thegradepointaveragesfor10randomlyselectedjuniorcollegestudentsarelistedbelow.Assumethegrade
pointaveragesarenormallydistributed.Finda98%confidenceintervalforthetruemean.Roundtothenearest
hundredth.
2.03.21.82.90.94.03.32.93.60.8
A) (1.55,3.53) B) (0.67,1.81) C) (2.12,3.14) D) (3.11,4.35)
17) Alocalbankneedsinformationconcerningthesavingsaccountbalancesofitscustomers.Arandomsampleof
15accountswaschecked.Themeanbalancewas$686.75withastandarddeviationof$256.20.Finda98%
confidenceintervalforthetruemean.Assumethattheaccountbalancesarenormallydistributed.Roundtothe
nearestcent.
A) ($513.17,$860.33) B) ($238.23,$326.41) C) ($326.21,$437.90) D) ($487.31,$563.80)
18) Tohelpconsumersassesstheriskstheyaretaking,theFoodandDrugAdministration(FDA)publishesthe
amountofnicotinefoundinallcommercialbrandsofcigarettes.Anewcigarettehasrecentlybeenmarketed.
TheFDAtestsonthiscigarettegaveameannicotinecontentof28.4milligramsandstandarddeviationof2.6
milligramsforasampleofn=9cigarettes.TheFDAclaimsthatthemeannicotinecontentexceeds31.0
milligramsforthisbrandofcigarette,andtheirstatedreliabilityis90%.Doyouagree?
A) No,sincethevalue31.0doesnotfallinthe90%confidenceinterval.
B) Yes,sincethevalue31.0doesfallinthe90%confidenceinterval.
C) Yes,sincethevalue31.0doesnotfallinthe90%confidenceinterval.
D) No,sincethevalue31.0doesfallinthe90%confidenceinterval.
SHORTANSWER.Writethewordorphrasethatbestcompleteseachstatementoranswersthequestion.
19) Inarandomsampleof26laptopcomputers,themeanrepaircostwas$170 withastandarddeviationof$34.
Assumethepopulationhasanormaldistribution.Constructa95%confidenceintervalforthepopulation
mean,μ.Supposeyoudidsomeresearchonrepaircostsforlaptopcomputersandfoundthatthestandard
deviationisσ=34.Usethenormaldistributiontoconstructa95%confidenceintervalforthepopulationmean,
μ.Comparetheresults.Roundtothenearestcent.
Page255