Chapter 19: Ionic Equilibria in Aqueous Systems
17. Buffer solutions with the component concentrations shown below were prepared. Which
of them should have the highest pH?
A) [H2PO4–] = 0.50 M, [HPO42–] = 0.50 M
B) [H2PO4–] = 1.0 M, [HPO42–] = 1.0 M
C) [H2PO4–] = 1.0 M, [HPO42–] = 0.50 M
D) [H2PO4–] = 0.50 M, [HPO42–] = 1.0 M
E) [H2PO4–] = 0.75 M, [HPO42–] = 1.0 M
18. A buffer is prepared by adding 0.5 mol of solid sodium hydroxide to 1.0 L of 1.0 M
acetic acid (CH3COOH). What is the pH of the buffer?
A) The pH will be pKa – 0.30, where pKa is that of acetic acid.
B) The pH will be greater than the pKa for acetic acid.
C) The pH will be less than the value in answer a.
D) The pH will be equal to the pKa for acetic acid.
E) More information is needed to solve the problem.
19. A solution is prepared by adding 100 mL of 0.2 M hydrochloric acid to 100 mL of 0.4 M
sodium formate. Is this a buffer solution, and if so, what is its pH?
A) It is a buffer, pH > pKa of formic acid.
B) It is a buffer, pH < pKa of formic acid.
C) It is a buffer, pH = pKa of formic acid.
D) It is a buffer, pH = pKb of sodium formate.
E) Since hydrochloric acid is a strong acid, this is not a buffer.
20. A buffer is prepared by adding 100 mL of 0.50 M sodium hydroxide to 100 mL of 0.75
M propanoic acid. Is this a buffer solution, and if so, what is its pH?
A) It is a buffer, pH > pKa of propanoic acid.
B) It is a buffer, pH < pKa of propanoic acid.
C) It is a buffer, pH = pKa of propanoic acid.
D) It is a buffer, pH = pKb of sodium propanoate.
E) Since sodium hydroxide is a strong base, this is not a buffer.
21. A solution is prepared by adding 500 mL of 0.3 M NaClO to 500 mL of 0.4 M HClO.
What is the pH of this solution?
A) The pH will be greater than the pKa of hypochlorous acid.
B) The pH will be less than the pKa of hypochlorous acid.
C) The pH will be equal to the pKa of hypochlorous acid.
D) The pH will equal the pKb of sodium hypochlorite.
E) The pH will be none of the above.