For the given hypothesis test, explain the meaning of a Type I error, a Type II error, or a correct decision as specified.
In the past, the mean running time for a certain type of flashlight battery has been 8.9 hours. The
manufacturer has introduced a change in the production method and wants to perform a
hypothesis test to determine whether the mean running time has increased as a result. The
hypotheses are:
H0: µ=8.9 hours
Ha: µ>8.9 hours
where µ is the mean running time of the new batteries . Explain the meaning of a Type II error.
A Type II error would occur if, in fact, µ>8.9 hours, but the results of the sampling lead to the
conclusion that µ<8.9 hours.
A Type II error would occur if, in fact, µ>8.9 hours, but the results of the sampling fail to
lead to that conclusion.
A Type II error would occur if, in fact, µ=8.9 hours, but the results of the sampling do not
lead to rejection of that fact.
A Type II error would occur if, in fact, µ=8.9 hours, but the results of the sampling lead to the
conclusion that µ>8.9 hours.
A sample mean, sample size, and population standard deviation are given. Use the one–mean z–test to perform the
required hypothesis test at the given significance level. Use the critical –value approach.
x=7.9, n = 18 , =1.7, H0: µ= 10; Ha: µ< 10, = 0.01
z= –5.24; critical value = –2.33; reject H0
z= –5.24; critical value = 1.96; do not reject H0
z= –5.24; critical value = –1.96; reject H0
z= –5.24; critical value = –2.33; do not reject H0
A sample mean, sample size, and population standard deviation are given. Use the one–mean z–test to perform the
required hypothesis test at the given significance level. Use the P–value approach.
x= 3.7, n = 32, = 1.8, H0: µ = 4.2 , Ha: µ < 4.2 , = 0.05
z = –1.57; P–value = 0.1164; do not reject H0
z = –1.57; P–value = 0.0582; reject H0
z = –1.57; P–value = 0.1164; reject H0
z = –1.57; P–value = 0.0582; do not reject H0.