Answers many vary. One possibility: Odd powers of negative numbers are negative, hence negative numbers can have
odd roots.
No. When n is an odd positive integer, nxn= x, as in 3(-5)3= –5, but when n is an even positive integer,
nxn = x, as in 4(-5)4 = -5 = 5. (Explanations will vary.)
The exponent was not applied to the numerical coefficient.
Mistake: You cannot take the square root of a number, using the radical symbol, and obtain a negative number as the
result.
Correct: There is no solution.
Mistake: Divided the radicands without evaluating the root
Correct: 2
Mistake: Squared 4 in the radicand
Correct: 45
Each radical represents a whole number.
Mistake: Divided instead of evaluating the square root
Correct: 2
False. The quotient rule for radicals also includes the stipulation that na and nb are both real numbers. If n is even
and a (or b) is negative, then na (or nb) is not real and the quotient rule for radicals does not apply.
Mistake: Multiplied by 11 instead of 11
Correct: 33
11
Indexes must be the same to combine terms.
The statement is false. Let n = a = b = 1; 1 + 1 2. (Examples will vary.)
Answers may vary. One possibility: First, satisfy the power in the denominator of the exponent by taking the cube root.
Then, multiply the result by the power in the numerator of the exponent.
The statement is false. The correct answer is 3x2. It is obtained by applying the product rule for radicals. The answer
would be x if you were multiplying square roots, not cube roots. (Explanations will vary.)
Answers will vary. One possibility: 3-13 =3–1 ·13 =3-1 ·313 = –313.
The statement is false. The correct answer is x.
4x·4x=4x2 by the product rule for radicals.
Then4x2=x2/4 =x1/2 =x. (Explanations will vary.)