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Solve the formula for the specified variable. Assume all variables represent nonnegative numbers. If possible, simplify
radicals and rationalize denominators.
272)
F =
Gm1m2
d2 for d
272)
A)
d =
Gm1m2F
F
B)
d =
Gm1m2
2F
C)
d =
Gm1m2
F
D)
d =Gm1m2F
Write a quadratic equation in standard form with the given solution set.
273)
{-1, 8}
273)
A)
x2- 8x + 7 = 0
B)
x2- 7x - 8 = 0
C)
x2+ 8x + 7 = 0
D)
x2+ 7x - 8 = 0
Sketch the graph of the quadratic function. Give the vertex and axis of symmetry.
274)
y +1=(x - 1)2
274)
93
A)
vertex: (- 1, - 1)
axis of symmetry: x = - 1
B)
vertex: (1, 1)
axis of symmetry: x =1
C)
vertex: (1, - 1)
axis of symmetry: x =1
D)
vertex: (- 1, 1)
axis of symmetry: x = - 1
Determine whether the given quadratic function has a minimum value or maximum value. Then find the minimum or
maximum value and determine where it occurs.
275)
f(x) = x2- 2x - 2
275)
A)
Maximum is 1 at x = - 3.
B)
Minimum is 1 at x = - 3.
C)
Minimum is - 3 at x =1.
D)
Maximum is - 3 at x =1.
D)
Sketch the graph of the quadratic function. Give the vertex and axis of symmetry.
94
276)
f(x) =1- (x + 1)2
276)
A)
vertex: (1, 1)
axis of symmetry: x =1
B)
vertex: (- 1, - 1)
axis of symmetry: x = - 1
C)
vertex: (1, - 1)
axis of symmetry: x =1
D)
vertex: (- 1, 1)
axis of symmetry: x = - 1
95
Find the intercepts of the quadratic function.
277)
y +9=(x - 3)2
277)
A)
x-intercepts: (0, 0) and (6, 0)
y-intercept: none
B)
x-intercepts: (0, 0) and (6, 0)
y-intercept: (0, 0)
C)
x-intercepts: (0, 0) and (-6, 0)
y-intercept: (0, 0)
D)
x-intercepts: (0, 0)
y-intercept: (0, 0)
Complete the square for the binomial. Then factor the resulting perfect square trinomial.
278)
x2- 12x
278)
A)
144; x2- 12x +144 =(x - 12)2
B)
144; x2- 12x -144 =(x - 12)2
C)
36; x2- 12x -36 =(x -6)2
D)
36; x2- 12x +36 =(x -6)2
Solve the equation by the square root property. If possible, simplify radicals or rationalize denominators. Express
imaginary solutions in the form a +
bi.
279)
3x2=45
279)
A)
{±15}
B)
{22.5}
C)
{16}
D)
{±15}
Find the coordinates of the vertex for the parabola defined by the given quadratic function.
280)
f(x) = x2+ 8
280)
A)
(0, -8)
B)
(0, 8)
C)
(-8, 0)
D)
(8, 0)
D)
Write a quadratic equation in standard form with the given solution set.
281)
{6 + i, 6- i}
281)
A)
x2+12x -35 = 0
B)
x2+12x -37 = 0
C)
x2-12x +35 = 0
D)
x2-12x +37 = 0
96
Solve the equation by the square root property. If possible, simplify radicals or rationalize denominators. Express
imaginary solutions in the form a +
bi.
282)
(x + 4)2=28
282)
A)
{±2 7}
B)
{-4± 2 14}
C)
{2 7±4}
D)
{-4± 2 7}
97
Answer Key
Testname: C8
Answer Key
Testname: C8
Answer Key
Testname: C8
Answer Key
Testname: C8
Answer Key
Testname: C8
Answer Key
Testname: C8
