Exam
Name___________________________________
SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.
Provide an appropriate response.
1)
Generally, the normal probability plot for a data set must be roughly linear in order to
assume that the variable is approximately normally distributed. Should this rule be
interpreted more strictly for small data sets or for large data sets? Explain.
1)
2)
How does the standard normal distribution differ from a nonstandard normal distribution?
Why is it necessary to standardize in order to find percentages for nonstandard normal
variables?
2)
Construct a normal probability plot of the given data.
3)
The prices per gallon (in dollars) of regular unleaded gasoline at twelve service stations are
given below.
1.79 2.09 1.89 1.99
1.75 1.81 1.93 2.19
2.01 2.15 1.95 1.85
3)
1
Provide an appropriate response.
4)
A student wished to use a table of areas for the standard normal curve to find the z–score
having an area to its right of 0.52. The student started by looking for the closest area to 0.52
in the body of the table and reading off the corresponding z–score which was 0.05. She
then subtracted this z–score from 1 to get 0.95. Was her reasoning correct? If not, where did
she go wrong and how would you have solved the problem?
4)
5)
In assessing the normality of a data set, why is it easier to interpret a normal probability
plot than it is to interpret a histogram?
5)
6)
The area under the standard normal curve to the right of a z–score is 0.56. Explain how
you could use a table of areas to find the z–score.
6)
7)
Suppose that you know the area under the standard normal curve to the right of –1.7. How
could you use this to find the area under the standard normal curve to the right of 1.7?
Explain your reasoning.
7)
8)
Sketch a standard normal curve and shade the area between the z–scores –2.5 and –1.
8)
9)
For a variable with a density curve, what is the relationship between the percentage of all
possible observations of the variable that lie within any specified range and the
corresponding area under its density curve?
9)
10)
Sketch a standard normal curve and shade the area to the right of the z–score 1.6.
10)
Construct a normal probability plot of the given data.
11)
The weekly incomes (in dollars) of a sample of 12 nurses working at a Los Angeles hospital
are given below.
500 750 630 480
550 650 720 780
820 960 1200 770
11)
Provide an appropriate response.
12)
A normal probability plot is given below for a sample of scores on an aptitude test. Use the
plot to assess the normality of scores on this test. Explain your reasoning.
12)
13)
Suppose that you know the area under the standard normal curve between 1 and 3 and the
area under the standard normal curve to the left of 3. Without further consulting a table of
areas, how could you find the area under the standard normal curve to the left of 1?
Explain your reasoning by using a sketch of the standard normal curve.
13)
Construct a normal probability plot of the given data.
14)
The resting heart rates from a group of 9 men before starting a workout program are given
below.
58 70 63
48 60 55
45 51 69
14)
Provide an appropriate response.
15)
On the same axes sketch normal distributions with
a. µ= 6, = 4
b. µ= 6, = 2
c. µ= –6, = 2.
15)
16)
Suppose that scores on a test are normally distributed with a mean of 80 and a standard
deviation of 8. You have been asked to find the 70th percentile. After sketching a standard
normal curve and shading the area of interest, the next step in solving this problem is to
use the table of areas. Would you look for 0.7 in the body of the table or in the left–hand
column? Explain your reasoning.
16)
17)
A variable is normally distributed with a mean of 100 and a standard deviation of 10.
Which is larger, the percentage of observations between 80 and 90 or the percentage of
observations between 120 and 130? Explain your reasoning.
17)
18)
Which is larger, the area under the standard normal curve between –1 and 1, or the area
under the standard normal curve between 0 and 2? Explain your reasoning.
18)
19)
Suppose that you know the area under the standard normal curve to the right of –2. How
could you use this to find the area under the standard normal curve to the left of 2? Explain
your reasoning.
19)
20)
A variable is normally distributed. 42% of the possible observations of the variable lie
between 20 and 28. What information does this give you about the graph of the normal
curve for this variable?
20)
21)
A normal probability plot is given below for the lifetimes (in hours) of a sample of batteries
of a particular brand. Use the plot to assess the normality of the lifetimes of these batteries.
Explain your reasoning.
21)
22)
In assessing the normality of data, why is a normal probability plot especially
advantageous for small samples?
22)
23)
Suppose that you know the area under the standard normal curve to the right of 2 and the
area under the standard normal curve to the right of 1. Without further consulting a table
of areas, how could you find the area under the standard normal curve between 1 and 2?
Explain your reasoning.
23)
24)
Scores on an aptitude test are normally distributed with a mean of 400 and a standard
deviation of 60. Explain how you would find any given percentile.
24)
25)
Use a sketch of the standard normal curve to explain the difference between z–scores and
areas under the standard normal curve. What are the possible values for an area and what
are the possible values for a z–score?
25)
26)
A normal probability plot is given below for a sample of scores on an aptitude test. Use the
plot to identify outliers, if any. Explain your reasoning.
26)
27)
When a normal probability plot is constructed, which axis is used for the normal scores
(horizontal or vertical)?
27)
28)
A normal probability plot is given below for a sample of scores on an aptitude test. Use the
plot to identify outliers, if any. Explain your reasoning.
28)
29)
A normal probability plot is given below for a sample of scores on an aptitude test. Use the
plot to assess the normality of scores on this test. Explain your reasoning.
29)
30)
A normal probability plot is given below for the weekly incomes (in dollars) of a sample of
engineers in one town. Use the plot to identify outliers, if any. Explain your reasoning.
30)
31)
A normal probability plot is given below for the lifetimes (in hours) of batteries of a
particular type. Use the plot to identify outliers, if any. Explain your reasoning.
31)
Construct a normal probability plot of the given data.
32)
The systolic blood pressure (in mmHg) is given below for a sample of 12 men aged between
60 and 65. 127 135 118 164
143 130 125 153
120 173 140 180
32)
Provide an appropriate response.
33)
Suppose that scores on a test are normally distributed with a mean of 80 and a standard
deviation of 8. Read the two questions below.
A. What is the 90th percentile?
B. What percentage of students score less than 90?
Explain the difference between the two questions. Describe how the method for solving A
would differ from the the method for solving B. Be sure to include in your explanation a
description of how the table of areas would be used in each case.
33)
34)
Does the presence of an outlier in your data set necessarily mean that you cannot use the
normal model to interpret the data? Explain.
34)
35)
A curve has area 0.317 to the left of 5 and area 0.647 to the right of 5. Could this curve be a
density curve for some variable? Explain your answer.
35)
Construct a normal probability plot of the given data.
36)
The final exam scores for 15 students in a statistics course are given below.
95 70 60 82 40
62 97 57 32 75
78 85 68 54 88
36)
Provide an appropriate response.
37)
A normal probability plot is given below for the weekly incomes (in dollars) of a sample of
engineers in one town. Use the plot to assess the normality of the incomes of engineers in
this town. Explain your reasoning.
37)
38)
Two random variables are normally distributed with the same mean. One has a standard
deviation of 10 while the other has a standard deviation of 15. How will the graphs of the
two variables differ and how will they be alike?
38)
39)
A variable is normally distributed with a mean of 100 and a standard deviation of 10. A
student wanted to find the percentage of observations of the variable lying between 106
and 110. What is wrong with his solution?
Student’s solution:
z–scores: 106–100
10 = 0.6 110–100
10 = 1.0
Percentage of scores lying between 106 and 110
= difference between z–scores
= 1.0 – 0.6 = 0.4 = 40%
39)
16
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Find the indicated probability or percentage for the normally distributed variable.
40)
40)
A)
0.1357
B)
0.8413
C)
0.1550
D)
0.1587
Use a table of areas for the standard normal curve to find the required z–score.
41)
41)
A)
1.34
B)
1.26
C)
1.39
D)
1.45
Find the specified percentile, quartile, or decile.
42)
42)
A)
36.7
B)
29.4
C)
26.1
D)
33.4
Fill in the blanks by standardizing the normally distributed variable.
43)
43)
A)
1, 1.15
B)
–2, –1
C)
1, 2
D)
2, 4
17
Use the empirical rule to solve the problem.
44)
44)
A)
52, 76
B)
64, 76
C)
40, 88
D)
40, 64
Find the indicated probability or percentage for the normally distributed variable.
45)
45)
A)
0.9332
B)
0.0668
C)
0.4332
D)
0.5
Provide an appropriate response.
46)
46)
A)
True
B)
False
Use a table of areas to obtain the shaded area under the standard normal curve.
47)
47)
A)
0.1894
B)
0.6212
C)
0.8106
D)
0.3788
Find the indicated probability or percentage for the normally distributed variable.
48)
48)
A)
0.9599
B)
0.5589
C)
0.0401
D)
0.0802
Fill in the blanks by standardizing the normally distributed variable.
49)
49)
A)
left, 1.4
B)
right, 1
C)
right, 1.4
D)
left, –1.4
Use a table of areas for the standard normal curve to find the required z–score.
50)
50)
A)
–1.38
B)
1.03
C)
1.75
D)
1.82
51)
51)
A)
–1.26
B)
–1.45
C)
–1.39
D)
–1.34
Use a table of areas to obtain the shaded area under the standard normal curve.
52)
52)
A)
0.1020
B)
0.7960
C)
0.8980
D)
0.2040
53)
53)
A)
0.0594
B)
0.1188
C)
0.9406
D)
0.8812
Solve the problem.
54)
54)
A)
0.1782
B)
0.5407
C)
0.4591
D)
0.3415
Find the specified percentile, quartile, or decile.
55)
55)
A)
238
B)
244
C)
232.96
D)
249.04
21
Solve the problem.
56)
56)
A)
No. The distribution has outliers.
B)
No. The distribution is left–skewed.
C)
No. The distribution is right–skewed.
D)
Yes. The distribution is bell–shaped.
Find the specified percentile, quartile, or decile.
57)
57)
A)
161.7 mg/100mL
B)
123.9 mg/100mL
C)
107.7 mg/100mL
D)
165.3 mg/100mL
Fill in the blanks by standardizing the normally distributed variable.
58)
58)
A)
left, 2.4
B)
right, 2.4
C)
right, 12
D)
left, 1.2
22
Provide an appropriate response.
59)
59)
A)
a, b, d
B)
a and d
C)
a only
D)
a, b, c, d
Find the specified percentile, quartile, or decile.
60)
60)
A)
8.79 g
B)
8.72 g
C)
8.61 g
D)
8.58 g
Fill in the blanks by standardizing the normally distributed variable.
61)
61)
A)
0, 1
B)
–1.5, 1.5
C)
–0.5, 2.5
D)
–1, 2
Use a table of areas to find the specified area under the standard normal curve.
62)
62)
A)
–0.0344
B)
0.9656
C)
0.0344
D)
0.4656
Solve the problem.
63)
63)
A)
Yes. The distribution is bell–shaped.
B)
No. The distribution is J–shaped.
C)
No. The distribution is left–skewed.
D)
No. The distribution is right–skewed.
Fill in the blanks by standardizing the normally distributed variable.
64)
64)
A)
left, –0.5
B)
left, 0.5
C)
right, 0.5
D)
right, 0.83
24
Provide an appropriate response.
65)
65)
A)
a, b, d
B)
a, b, c, d
C)
c, e
D)
b, d
Use a table of areas to find the specified area under the standard normal curve.
66)
66)
A)
0.4951
B)
0.2239
C)
–0.2237
D)
0.2237
Fill in the blanks by standardizing the normally distributed variable.
67)
67)
A)
left, 0.33
B)
left, 0.87
C)
right, 0.33
D)
right, –0.33
25
Use the empirical rule to solve the problem.
68)
68)
A)
95.44%
B)
99.74%
C)
68.26%
D)
99.99%
Use a table of areas to find the specified area under the standard normal curve.
69)
69)
A)
0.2776
B)
0.2190
C)
0.7224
D)
0.2224
Find the specified percentile, quartile, or decile.
70)
70)
A)
212.5
B)
207.8
C)
211.3
D)
187.5
Find the indicated probability or percentage for the normally distributed variable.
71)
71)
A)
0.2257
B)
0.3811
C)
0.0703
D)
0.1554
26
Use a table of areas to obtain the shaded area under the standard normal curve.
72)
72)
A)
0.7198
B)
0.2802
C)
0.8599
D)
0.1401
Solve the problem.
73)
73)
A)
0.0999
B)
0.0525
C)
0.0342
D)
0.9473
Find the specified percentile, quartile, or decile.
74)
74)
A)
24.865 inches
B)
35.935 inches
C)
28.132 inches
D)
32.668 inches
Solve the problem.
75)
75)
A)
No. The distribution has outliers.
B)
No. The distribution is left–skewed.
C)
Yes. The distribution is bell–shaped.
D)
No. The distribution is right–skewed.
Use the empirical rule to solve the problem.
76)
76)
A)
37.9, 48.1
B)
31.1, 37.9
C)
27.7, 48.1
D)
31.1, 44.7
28
Use a table of areas to find the specified area under the standard normal curve.
77)
77)
A)
0.7499
B)
1.2501
C)
0.7409
D)
0.2591
Find the indicated probability or percentage for the normally distributed variable.
78)
78)
A)
2.28%
B)
47.72%
C)
37.45%
D)
97.72%
Solve the problem.
79)
79)
A)
Yes. The distribution is bell–shaped.
B)
No. The distribution is right–skewed.
C)
No. The distribution is left–skewed.
D)
No. The distribution is uniform.
80)
80)
A)
No. The distribution is left–skewed.
B)
No. The distribution is uniform.
C)
No. The distribution is right–skewed.
D)
Yes. The distribution is bell–shaped.
Use a table of areas to obtain the shaded area under the standard normal curve.
81)
81)
A)
0.0602
B)
0.9699
C)
0.0301
D)
0.9398
Use the empirical rule to solve the problem.
82)
82)
A)
31.74%
B)
68.26%
C)
84.13%
D)
95.44%
30
83)
83)
A)
97.72%
B)
99.74%
C)
68.26%
D)
95.44%
Use a table of areas to find the specified area under the standard normal curve.
84)
84)
A)
0.1217
B)
0.5013
C)
0.4987
D)
0.9987
Use a table of areas for the standard normal curve to find the required z–score.
85)
85)
A)
1.26
B)
1.39
C)
1.45
D)
1.48
86)
86)
A)
–1.75 and 1.75
B)
0 and 2.05
C)
–2.05 and 2.05
D)
–2.33 and 2.33
Use the empirical rule to solve the problem.
87)
87)
A)
262.3, 274
B)
266.2, 281.8
C)
262.3, 285.7
D)
274, 281.8
31
88)
88)
A)
99.74%
B)
99.99%
C)
68.26%
D)
95.44%
Provide an appropriate response.
89)
89)
A)
a, b
B)
e
C)
b, c
D)
b
Find the indicated probability or percentage for the normally distributed variable.
90)
90)
A)
0.3821
B)
0.5987
C)
0.4013
D)
0.0987
32
Solve the problem.
91)
91)
A)
Yes. The distribution is bell–shaped.
B)
No. The distribution is right–skewed.
C)
No. The distribution is uniform.
D)
No. The distribution is left–skewed.
Use a table of areas to obtain the shaded area under the standard normal curve.
92)
92)
A)
0.1210
B)
0.2420
C)
0.7580
D)
0.8790
Solve the problem.
93)
93)
A)
No. The distribution is uniform.
B)
Yes. The distribution is bell–shaped.
C)
No. The distribution is right–skewed.
D)
No. The distribution is left–skewed.
94)
94)
A)
0.2060
B)
0.6766
C)
0.5832
D)
0.5493
Provide an appropriate response. Assume that the variable under consideration has a density curve.
95)
95)
A)
10, 11
B)
0.09, 0.1
C)
4.5, 5
D)
9, 10
Provide an appropriate response.
96)
96)
A)
a, b
B)
b, d
C)
a
D)
a, c
97)
97)
A)
True
B)
False
98)
98)
A)
True
B)
False
Solve the problem.
99)
99)
A)
No. The distribution is right–skewed.
B)
Yes. The distribution is bell–shaped.
C)
No. The distribution is left–skewed.
D)
No. The distribution is J–shaped.
Use a table of areas to find the specified area under the standard normal curve.
100)
100)
A)
0.9513
B)
0.0487
C)
0.9299
D)
0.0701
Use the empirical rule to solve the problem.
101)
101)
A)
99.74%
B)
68.26%
C)
84.13%
D)
95.44%
Find the specified percentile, quartile, or decile.
102)
102)
A)
64.3 inches
B)
67.8 inches
C)
65.3 inches
D)
66.1 inches
Find the indicated probability or percentage for the normally distributed variable.
103)
103)
A)
0.3370
B)
0.7477
C)
1.0847
D)
0.4107
Use a table of areas to obtain the shaded area under the standard normal curve.
104)
104)
A)
0.1788
B)
0.8212
C)
0.3576
D)
0.6424
Use a table of areas for the standard normal curve to find the required z–score.
105)
105)
A)
–0.25
B)
–0.57
C)
0.57
D)
0.25
Find the indicated probability or percentage for the normally distributed variable.
106)
106)
A)
1.62%
B)
2.48%
C)
1.96%
D)
0.0196%
Use the empirical rule to solve the problem.
107)
107)
A)
68.26%
B)
99.99%
C)
99.74%
D)
95.44%
38
Provide an appropriate response. Assume that the variable under consideration has a density curve.
108)
108)
A)
87.5%
B)
62.5%
C)
12.5%
D)
37.5%
Use a table of areas for the standard normal curve to find the required z–score.
109)
109)
A)
0.3264
B)
–0.13
C)
0.13
D)
0.6736
Find the indicated probability or percentage for the normally distributed variable.
110)
110)
A)
0.0179
B)
0.0166
C)
0.4834
D)
0.9834
Use a table of areas for the standard normal curve to find the required z–score.
111)
111)
A)
–1.89
B)
–1.48
C)
–1.63
D)
–1.75
Find the specified percentile, quartile, or decile.
112)
112)
A)
9.7 years
B)
10.3 years
C)
8.1 years
D)
9.4 years
39
113)
113)
A)
$65.03
B)
$61.25
C)
$52.97
D)
$54.5
Solve the problem.
114)
114)
A)
No. The distribution is uniform.
B)
No. The distribution is right–skewed.
C)
No. The distribution is left–skewed.
D)
Yes. The distribution is bell–shaped.
Use a table of areas for the standard normal curve to find the required z–score.
115)
115)
A)
–1.46, 1.46
B)
–1.45, 1.45
C)
–1.53, 1.53
D)
–1.39, 1.39
Provide an appropriate response. Assume that the variable under consideration has a density curve.
116)
116)
A)
0.311
B)
0.439
C)
0.189
D)
0.689
Use a table of areas to obtain the shaded area under the standard normal curve.
117)
117)
A)
0.9792
B)
0.0104
C)
0.9896
D)
0.0208
Provide an appropriate response. Assume that the variable under consideration has a density curve.
118)
118)
A)
28%
B)
47%
C)
72%
D)
53%
Use a table of areas to obtain the shaded area under the standard normal curve.
119)
119)
A)
0.0129
B)
0.9871
C)
0.9742
D)
0.0258
Use a table of areas for the standard normal curve to find the required z–score.
120)
120)
A)
–1.08
B)
1.08
C)
0.5557
D)
0.8051
Find the specified percentile, quartile, or decile.
121)
121)
A)
3.135
B)
3.175
C)
2.465
D)
3.05
42
Solve the problem.
122)
122)
A)
No. The distribution is right–skewed.
B)
No. The distribution is left–skewed.
C)
Yes. The distribution is bell–shaped.
D)
No. The distribution is uniform.
Provide an appropriate response.
123)
123)
A)
a, b
B)
a
C)
a, c
D)
b, c
Use a table of areas to obtain the shaded area under the standard normal curve.
124)
124)
A)
0.0366
B)
0.0183
C)
0.9634
D)
0.9817
Use a table of areas to find the specified area under the standard normal curve.
125)
125)
A)
0.8907
B)
0.8485
C)
0.1292
D)
0.8708
126)
126)
A)
0.4884
B)
0.7557
C)
0.2211
D)
1.54
Find the indicated probability or percentage for the normally distributed variable.
127)
127)
A)
9.18%
B)
40.82%
C)
35.31%
D)
90.82%
44
Answer Key
Testname: C6
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Answer Key
Testname: C6
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Answer Key
Testname: C6
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Answer Key
Testname: C6
Answer Key
Testname: C6
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Answer Key
Testname: C6