153)
7x2y4+42x2y3= 7x2y3( )
153)
A)
y +6x2
B)
7y +6x
C)
x2y +6
D)
y +6
154)
–14z9= – 2z7( )
154)
A)
28z
B)
7z7
C)
7z2
D)
–7z2
Factor out the greatest common factor.
155)
18x9y8– 48x6y6– 24x3y2
155)
A)
6x3y2(3x6y6– 8x3y4– 4)
B)
6(3x9y8– 8x6y6– 4x3y2)
C)
No common factor (except 1)
D)
6x3(3x6y8– 8x3y6– 4y2)
Factor completely. If the polynomial is prime, say so.
156)
–3x2+30x –75
156)
A)
Prime
B)
3(x –5)2
C)
3(x +5)2
D)
–3(x –5)2
Find the greatest common factor of the terms.
157)
14m3, 56m7, 196m4
157)
A)
56m3
B)
14m4
C)
784m4
D)
14m3
Solve the equation.
158)
(5y + 16)(4y + 17) = 0
158)
A)
–5
11 , –4
17
B)
16
5, 17
4
C)
{11, 13}
D)
–16
5, –17
4
Factor by grouping.
159)
24r2+54ry –4xr –9xy
159)
A)
(4r +9y)(6x – r)
B)
(9r +4y)(6r – x)
C)
(4r +9y)(x –6r)
D)
(4r +9y)(6r – x)
D
Factor the binomial completely. If it is prime, say so.
160)
147a4b – 12b3
160)
A)
3b(7a2+ 2b)(7a2– 2b)
B)
3b(7a + 2b)2
C)
3b(7a – 2b)2
D)
Prime
A
Solve the equation.
161)
(x – 5)2+x2=(x + 5)2
161)
A)
{–20}
B)
{0, 20}
C)
{0, –20}
D)
{20}
B
Complete the factoring.
162)
x2– 14x + 48 = (x – 6)( )
162)
A)
x2+ 6
B)
x + 8
C)
6– x
D)
x – 8
D
33
D
Solve the problem.
163)
A painter leans a ladder against one wall of a house. The ladder is 26 ft long. The base of the ladder
is 23 ft from the house. How high is the wall? Round approximations to the nearest tenth.
?26 ft
23 ft
163)
A)
6.1 ft
B)
24.5 ft
C)
12.1 ft
D)
73.5 ft
Complete the factoring.
164)
x2– 3x – 54 = (x + 6)( )
164)
A)
x – 9
B)
–x – 9
C)
x + 9
D)
9– x
Solve the equation.
165)
(x – 3)(x2– 8x + 12) = 0
165)
A)
{–3}
B)
{3, 6, 2}
C)
{3}
D)
{–3, –6, –2}
Provide an appropriate response.
166)
Is x3y7 a common factor of x4y9 and x2y7?
166)
A)
No
B)
Yes
Factor by grouping.
167)
20a3+ 8a2b – 15ab2– 6b3
167)
A)
(4a2– 3b)(5a + 2b)
B)
(4a2– 3b2)(5a + 2b)
C)
(20a2– 3b2)(a + 2b)
D)
(4a2+ 3b2)(5a – 2b)
34
Solve the equation.
168)
3y(5y +9) =6
168)
A)
–1
5, 2
B)
1
5, 2
C)
1
5, –2
D)
1
5
Factor the binomial completely. If it is prime, say so.
169)
4x2+ 25
169)
A)
(2x – 5)2
B)
(2x + 5)2
C)
(2x + 5)(2x – 5)
D)
Prime
Provide an appropriate response.
170)
Find a quadratic equation having the given solutions.
x = – 1
4 or x = – 1
2
170)
A)
8x2+ 6x + 1 = 0
B)
8x2– 6x + 1 = 0
C)
4x2+ 4x + 1 = 0
D)
4x2– 4x – 1 = 0
Factor by grouping.
171)
6–2y –3p +yp
171)
A)
(3 +y)(2+p)
B)
(3 –y)(2–p)
C)
(3 +y)(2–p)
D)
(3 –y)(2+p)
Factor completely.
172)
x2+ 24x + 144
172)
A)
(x + 12)2
B)
(x + 12)(x – 12)
C)
(x – 12)2
D)
Prime
35
Factor by grouping.
173)
8z2+ 6z – 9
173)
A)
(8z + 3)(z – 3)
B)
(2z + 3)(4z – 3)
C)
(2z – 3)(4z + 3)
D)
Prime
Solve the problem.
174)
A ladder is resting against a wall. The top of the ladder touches the wall at a height of 12 feet. Find
the length of the ladder if the length is 4 feet more than its distance from the wall.
174)
A)
16 ft
B)
24 ft
C)
12 ft
D)
20 ft
175)
The height of a box is 3 inches. Its length is 4 inches more than its width. Find the length if the
volume is 96 cubic inches.
175)
A)
4 in.
B)
3 in.
C)
32 in.
D)
8 in.
Solve the equation.
176)
6k2– 47k – 8 = 0
176)
A)
–1
6, 6
B)
{–6, 8}
C)
1
47 , –1
6
D)
–1
6, 8
177)
x2+ 3x – 18 = 0
177)
A)
{6, 3}
B)
{–6, 3}
C)
{–6, 1}
D)
{6, –3}
36
Answer Key
Testname: C5
37
Answer Key
Testname: C5
Answer Key
Testname: C5
Answer Key
Testname: C5
Answer Key
Testname: C5