89) A solution may contain the following ions Ag+, Cu2+, Cd2+, Mn2+, Ni2+ and Na+. A white
precipitate formed when 0.10 M NaCl was added and after this was removed the solution was treated
with H2S gas under acidic conditions and no precipitate formed. When the solution was made basic and
again treated with H2S gas a dark colored precipitate formed. If no further tests were made then what
conclusions can you draw?
A) possible ions present Ag+, Mn2+, Ni2+
B) possible ions present Ag+, Mn2+, Ni2+, Na+
C) possible ions present Ag+, Cu2+, Cd2+
D) possible ions present Ag+, Cu2+, Cd2+, Na+
90) A solution may contain the following ions Ag+, Cu2+, Mn2+, Ca2+, and Na+. No precipitate
formed when 0.10 M NaCl was added but a dark colored precipitate formed when H2S was added to an
acidic portion of the solution. After the removal of the solid the solution was made basic and more H2S
was added and a dark precipitate again formed. Treatment of the filtrate with (NH4)2CO3 resulted in a
white precipitate. If no further tests were made then what conclusions can you draw?
A) possible ions present Cu2+, Mn2+, Na+
B) possible ions present Cu2+, Mn2+, Ca2+
C) possible ions present Cu2+, Mn2+, Ca2+, Na+
D) possible ions present Ag+, Cu2+, Mn2+, Ca2+, Na+
91) Which set of ions precipitate as sulfides?
A) Ag+, Pb2+, Mn2+
B) Pb2+, Fe2+, Ca2+
C) Co2+, Ba2+, K+
D) NH4+, Na+, K+
92) Which pair of ions can be separated by the addition of chloride ion?
A) Ag+ and Co2+
B) Cu2+ and Bi3+
C) Pb2+ and Hg22+
D) Ca2+ and Ba2+