The graphing calculator screen shows the graphs of the two given functions, and the display gives the coordinates of one
of the solutions. Find the other solution.
139)
y =1
2x2
x – y = – 4
139)
A)
(–2, –2)
B)
(–2, 2)
C)
(2, –2)
D)
(2, 2)
Graph the hyperbola.
140)
y2
4–x2
16 = 1
140)
A)
B)
76
C)
D)
Graph the rational function.
141)
f(x) =4
x+ 1
141)
A)
B)
77
C)
D)
Graph the circle.
142)
x2+ y2– 2x – 4y + 1 = 0
142)
A)
B)
78
C)
D)
The circle or ellipse shown in the calculator–generated graph was created using function mode with a square viewing
window. What are the two functions y1 and y2 that were used to obtain the graph whose equation is given?
143)
(x – 1)2+ (y – 1)2= 1
143)
A)
y1= – 1 +1 –(x – 1)2, y2= 1 –1 –(x – 1)2
B)
y1= – 1 +1 –(x – 1)2, y2= – 1 –1 –(x – 1)2
C)
y1= 1 +1 –(x – 1)2, y2= 1 –1 –(x – 1)2
D)
y1= 1 +1 –(x – 1)2, y2= – 1 –1 –(x – 1)2
79
Solve the system by the elimination method or a combination of the elimination and substitution methods.
144)
xy =11
2y2–x2=11
144)
A)
–22, –1
2 , (11, 1)
B)
i22, –i22
2 , –i22, i22
2 , 11, 11 , –11, –11
C)
i22, –i22
2 , 11, 11
D)
2i 11, –i11 , – 2i 11, i 11 , 11, 11 , –11, –11
Find the center and radius of the circle.
145)
x2+ y2– 18x + 4y + 36 = 0
145)
A)
(–2, 9); r =7
B)
(–9, 2); r =49
C)
(2, –9); r =49
D)
(9, –2); r =7
Find the equation of a circle satisfying the given conditions.
146)
Center: (2, –9); radius: 9
146)
A)
(x – 2)2+ (y + 9)2=81
B)
(x + 2)2+ (y – 9)2=81
C)
(x – 9)2+ (y + 2)2=9
D)
(x + 9)2+ (y – 2)2=9
Evaluate the expression.
147)
[[6.5]]
147)
A)
7
B)
–6
C)
5
D)
6
The hyperbola shown in the calculator–generated graph was graphed in function mode with a square viewing window.
What are the two functions y1 and y2 that were used to obtain the graph whose equation is given?
148)
x2
49 –y2= 1
10
–15 15
–10
148)
A)
y1=x2
49 + 1, y2= – x2
49 + 1
B)
y1=x2+ 49, y2= – x2+ 49
C)
y1=x2
49 – 1, y2= – x2
49 – 1
D)
y1=x2– 49, y2= – x2– 49
Solve the problem.
149)
An elliptical riding path is to be built on a rectangular piece of property that measures 6 mi by 4 mi.
Find an equation for the ellipse, where x and y are measured in mi, if the path is to touch the center
of the property line on all 4 sides.
6 mi
4 mi
149)
A)
x2
4 +y2
9 = 1
B)
x2
9 +y2
4 = 1
C)
x2
36 +y2
4 = 1
D)
x2
4 +y2
36 = 1
81
Solve the system by the elimination method or a combination of the elimination and substitution methods.
150)
x2+ y2=16
x2– y2=16
150)
A)
{(–4, 0), (–4, 4)}
B)
{(4, 4), (–4, 4)}
C)
{(4, 0), (4, 4)}
D)
{(4, 0), (–4, 0)}
82
Answer Key
Testname: C13
Answer Key
Testname: C13
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Answer Key
Testname: C13
85
Answer Key
Testname: C13
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Answer Key
Testname: C13
Answer Key
Testname: C13
Answer Key
Testname: C13