12.3 Short Answer Questions
1) For the reaction shown below, if the rate of formation of O2 is 6.0 × 10–6 M/s, the rate of
decomposition of N2O5 over the same time interval is ________.
2 N2O5(g) → 4 NO2(g) + O2(g)
2) The reaction shown below has the rate law: Rate = k[BrO3–][Br–][H+]2. The order of
reaction with respect to H+ is ________ and the overall order is ________.
BrO3–(aq) + 5 Br–(aq) + 6 H+(aq) → 3 Br2(aq) + 3 H2O(l)
3) At 300°C decomposition of NO2(g) occurs with a rate law: Rate = – k[NO2]x. If the initial
rate of decomposition is 3.2 × 10–5 M/s when [NO2]o = 8.0 × 10–3 M and the initial rate of
decomposition is 8.0 × 10–6 M/s when [NO2]o = 4.0 × 10–3 M, then the order of reaction with
respect to NO2, x = ________.
4) The decomposition of hydrogen peroxide occurs according to the equation
2 H2O2(aq) → 2 H2O(l) + O2(g)
A concentration-time study of this reaction produces a straight line when ln[H2O2] is plotted
versus time. Therefore, this is a ________ order reaction.
5) At 55° the decomposition of N2O5 is first order, having a rate constant, k = 1.7 × 10–3 s–1. If
the initial concentration of N2O5 is 6.4 × 10–3 M, the number of half-lives that are required for
the N2O5 concentration to fall to 2.0 × 10–4 M is ________, and the amount of time required is
________ minutes.