Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
117. The N – N – H bond angles in hydrazine N2H4 are 112. What is the hybridization of the
nitrogen orbitals predicted by valence bond theory?
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
118.
Select True or False: N,N-diethyl-m-tolumide (DEET) is the active ingredient in many mosquito repellents.
There are 30 sigma bonds and 4 pi bonds are contained in a DEET molecule.
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
119.
Select True or False: Ibuprofen is used as an analgesic for the relief of pain, and also to help reduce fever.
How many sigma bonds and pi bonds are contained in an ibuprofen molecule?
33 sigma bonds and 4 pi bonds
120. Select True or False: There are two –bonds in C2H4.
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
123. Select True or False: According to the VSEPR theory, the geometrical structure of PF5 is
trigonal bipyramidal.
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
124.
Shown here is the correct Lewis structure for PF5. According to VSEPR theory how many electrons are bonded to the P
atom?
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
125. Which bond angles are present in a molecule with an octahedral geometry?
126. List all of the bond angles present in a molecule with a trigonal bipyramidal geometry.
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
127. What bond angles are predicted by VSEPR theory for the F –P –F bonds in PF5?
128. Select True or False: According to the VSEPR theory, the molecule PF5 will be polar.
129. Select True or False: The geometrical structure of PF5 and IF5 are both square
pyramidal.
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
130. Select True or False: Ozone (O3) is an allotropic form of oxygen. According to VSEPR
theory the shape of the ozone molecule is bent.
131. Select True or False: The bond in B2 is longer than the bond in B2–.
132. Select True or False: The bond in O2 is shorter than the bond in O2+.
133.
In the following list, which entry is NOT accurate?
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
134. In benzene (C6H6), what is the hybridization of each carbon atom?
135. Which of the following molecules is polar?
CH3OH
H2O
CH3OCH3
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
136. Select True or False: According to the VSEPR theory, all of the electron pair-electron
137. Select True or False: The BrF5 molecule has polar bonds and has a net dipole moment.
138. Select True or False: Pi bonds are covalent bonds in which the electron density is
concentrated above and below a plane containing the nuclei of the bonding atoms.
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
139. Select True or False: The hybridization of B in the BF3 molecule is sp3.
140. Select True or False: A bonding molecular orbital is of lower energy (more stable) than
the atomic orbitals from which it was formed.
141. Select True or False: A species with a bond order of 1/2 may be stable.
142. Select True or False: More energy is required to break a bond with an order of 3/2 than is
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
143. Select True or False: Two px orbitals from two different atoms can interact to form a
sigma bonding molecular orbital.
144. Select True or False: Two py orbitals from two different atoms can interact to form a pi
bonding molecular orbital.
145. Select True or False: The geometry of the hybrid orbitals of the central atom of a
Chapter 10 – Chemical Bonding II: Molecular Geometry and Hybridization of Atomic
146. Select True or False: Valence Bond Theory alone can be used to determine that O2 is
147. Select True or False: A molecule with polar bonds must be a polar molecule in all cases.