Chapter 15 Metabolism: Basic Concepts and Design
You are interested in studying bacteria found in peat swamps and you identify a new bacterium
that you believe is a chemotroph. Which of the following would you use to verify your belief?
screen for enzymes that oxidize carbon
screen for light gathering structures
screen for digestive enzymes
screen for linked reactions
The formation of ATP by creatine kinase is shown in the reaction below:
creatine phosphate + ADP ↔ ATP + creatine
Using the Table of Standard Free Energies (Table 15.1 in text), determine if this reaction is
thermodynamically favored under standard conditions.
No, it is not thermodynamically favored because the Kˊeq is 12.6.
No, it is not thermodynamically favored because the ΔGoˊis 12.6 kJ/mol.
No, it is not thermodynamically favored because the ΔGoˊis is -73.6 kJ/mol.
Yes, it is thermodynamically favored because the Kˊeq is 73.6.
Yes, it is thermodynamically favored because the ΔGoˊis is -12.6 kJ/mol.
The hydrolysis of a phosphate group from ATP releases 30.5 kj/mol, whereas the hydrolysis of a
phosphate from glucose 6-phosphate releases only 13.82 kJ/mol. In that the product is the same,
what accounts for the difference?
ATP has greater resonance stabilization than the product orthophosphate.
There is a greater increase in entropy when ATP is hydrolyzed.
Water hydrates ATP greater than glucose 6-phosphate.
ATP has a larger phosphoryl-transfer potential.
The phosphate ester in ATP is more thermodynamically stable than in glucose 6-
phosphate.
Explain how a metabolic pathway can contain an energetically unfavorable reaction yet still
occur.
The free-energy changes of the individual steps in a pathway are summed to determine
the overall free-energy change. Thus, a step that might not normally occur can be driven
if it is coupled to a thermodynamically stable reaction.
What are the two criteria that must be satisfied by a biochemical pathway?
Ans: C Section: 15.1