NAME 79
course as a function of the three variables, P1,P2,andM:S=M
If this student wants to get an overall score of S, with the smallest pos-
(b) Suppose that a student has the utility function
U(S, M)=S−A
2M2,
where Sis the student’s overall score for the course, Mis the number
of minutes the student spends studying, and Ais a variable that reflects
how much the student dislikes studying. In Part (a) of this problem, you
found that a student who studies for Mminutes and allocates this time
wisely between the two exams will get an overall score of S=M
P1+P2.
Substitute M
P1+P2for Sin the utility function and then differentiate with
respect to Mto find the amount of study time, M, that maximizes the
student’s utility. M=1
A(P1+P2).Your answer will be a function of
the variables P1,P2,andA. If the student chooses the utility-maximizing
amount of study time and allocates it wisely between the two exams, he
or she will have an overall score for the course of S=1
A(P1+P2)2.
(c) Nancy Lerner has a utility function like the one presented above. She
chose the utility-maximizing amount of study time for herself. For Nancy,
P1=10andP2= 20. She spent a total of M=1,200 minutes studying
for the two exams. This gives us enough information to solve for the
variable Ain Nancy’s utility function. In fact, for Nancy, A=1
36,000.
(d) Ed Fungus is a student in Nancy’s class. Ed’s utility function is just
like Nancy’s, with the same value of A. But Ed learns more slowly than
Nancy. In fact it takes Ed exactly twice as long to learn anything as it
takes Nancy, so that for him, P1=20andP2= 40. Ed also chooses his
amount of study time so as to maximize his utility. Find the ratio of the
amount of time Ed spends studying to the amount of time Nancy spends
6.13 (1) Here is a puzzle for you. At first glance, it would appear that
there is not nearly enough information to answer this question. But when
you graph the indifference curve and think about it a little, you will see
that there is a neat, easily calculated solution.