ANDREA FLORENCE G. VIDAL RESEARCH
BSA 3
PART 2
Activity 1. Read and answer the following questions:
Miss Cruz was tasked to select a student to represent the school in the Math Olympiad. She is
considering two students whose grades in the last six long quizzes are given below.
Stephanie 34 36 42 30 40 28
Cecilia 46 19 45 30 20 50
a. What is the mean score of Stephanie? Cecilia? STEPHANIE: 35 CECILIA: 35
b. Whose score is more spread? CECILIA
c. If you are Miss Cruz , who between the two students will you choose to represent the school?
Why? I WILL CHOOSE STEPHANIE BECAUSE HER GRADE IS CONTAINED NEAR THE
AVERAGE
d. How can dispersion of data be measured? BY USING THE STANDARD DEVIATION
e. What does the small value for the measure of dispersion indicate?If a measure of dispersion
has a low value, it indicates that the data is closely clustered, such as around the arithmetic mean.
As a result, the mean is thought to be descriptive of the data and therefore trustworthy.
f. What does the large value for the measure of dispersion indicate?A high level of dispersion
means that the mean is unreliable and does not accurately represent the results.
g. What is an outlier? AN EXTREME SCORE OR THE HIGHEST OR LOWEST SCORE OF THE
DATA.
Activity 2. Find the mean deviations of the scores of Cecilia.
Cecilia
46
19
45
30
20
50
Cecilia
x
x – x
̅
⎜x – x
̅ ⎜
46
46 – 35
11
19
19 – 35
16
45
45 – 35
10
30
30 – 35
5
20
20 – 35
15
50
50 – 35
15
35
∑ = 72
= 12
Activity 3. Given the scores x, find the variance and standard deviation
X
(𝑥 − 𝑥̄)2
12
16.5
272.25
32
3.5
12.25
28
.5
.25
34
5.5
30.25
30
1.5
2.25
35
6.5
42.25
=
171/6=28.5
=34
=359.50
Computation
Answer
= 34/6
5.67
=359.5/6-1
71.9
=sqrt 71.8
8.48
