Duu = D0 * ud * ud = 10,000 * 150% * 150% = 22,500
Dud = D0 * ud = 10,000 * 150% = 15,000
Ddd = D0 = 10,000
Ddu = D0 * ud = 10,000 * 150% = 15,000
Please note that Duu = 22,500 exceeds the capacity of 20,000, hence Moon Micro can
only set 20,000 demand in this scenario. And we should calculate revenue of this scenario
accordingly.
Independent of demand changes, cost per server by Molectron in the 2nd yr. also has two
scenarios. It can remain the same at CMolectron = $2,000, or goes up to CMolectron * uc =
$2,000 * 120% = $2,400. Together with the four possible variations due to demand
changes, there are eight scenarios in the second year. For each scenario, we need to
evaluate its probability, incremental revenue, and profit.
We present here how to compute these critical quantifications for one scenario. Analyses
for other scenarios are summarized in the table following this analysis. In this scenario,
the demand has been going up and up for two years and Molectron raised the cost per
server in the second year. This scenario is represented in the decision tree as the upper
right-hand node.
1. The total probability of Duu and cost per server by Molectron going up is:
80% * 80% * 50% = 32%.
2. The incremental revenue of this scenario should we take first option is:
{ min(capacity, Du ) + min(capacity, Duu) – D0 } * P = $225,000,000
3. The incremental revenue of this scenario should we take second option is:
( Du + Duu – D0 ) * P = $262,500,000
Please note that under the first option, Moon Micro has only 20,000 capacities hence
exceeding demand can not be satisfied. However under the second option, Molectron has
capacities to handle extra demands.
4. The incremental cost of this scenario should we take option one is:
Cfix * 2 + { min(capacity, Du ) + min(capacity, Duu) – D0 } * (C labor + Craw) =
$147,500,000
5. The incremental cost of this scenario should we take option two is:
( Du – D0 ) * ( CMolectron + Craw) + (Duu – D0) * (CMolectron * uc + Craw ) = $180,000,000
6. Hence for the scenario of Duu and cost per server by Molectron also going up, the
incremental profit of option one is $225,000,000 – $147,500,000 = $77,500,000; while
the incremental profit of option two is $262,500,000 – $180,000,000 = $82,500,000.
Similarly we can calculate the profits of option one and option two for each one of the
eight scenarios. The details are shown in the following table. The expected incremental
profit is calculated by the sum of products of incremental profits and associated
probabilities.