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95 Chapter 10 10.1 Eq. (10.18): )1( * (net)   qpp NqAQ 2 21 kN/m 4.146)6.17)(3()6.15)(6(  sc LLq 222 m 14.3)2( 44     bp DA Eq. (10.19): 59.8021.021.0 )35)(17.0(17.0*  eeNq 5.4 2 36  […]

107 Chapter 11 11.1 Gs = 2.74; w = 9.81 kN/m3 From Eq. (11.5): LL0274.01 88.26 100 LL )74.2(1 )81.9)(74.2( ))(LL(1              s ws dG G LL d […]

113 Chapter 12 12.1 Ko = (1 – sin 30)(2)sin30 = 0.707 Eq. (12.5): ooo KHHqKPPP 2 21 2 lb/ft 5497.6  )707.0()12)(108( 2 1 )0( 2 ft 4 3 12 H z 1 3 12.2 Ko = 1 – […]

121 Chapter 13 13.1 Refer to the diagram. 10 ;32 1 . From Table 12.3, Ka = 0.321. kN/m 247.31)321.0)(8.16()577.9( 2 1 )( 2 12 1 2  aa KHP kN/m 42.9410sin  av PP ; kN/m 55.24310cos  ah […]

Chapter 14 14.1 a. Refer to Figure 14.9 in the text. L1 = 4 m; L2 = 8 m;  = 32  = 16.1 kN/m3; sat = 18.2 kN/m3;  = 18.2 – 9.81 = 8.39 kN/m3 307.0 2 […]

147 Chapter 15 15.1 Eq. (15.5): 2 22 kN/m 19.46 2 35 45tan)5.6)(17)(65.0( 2 45tan65.065.0               HHKaa 0 1 B M kN/m 43.79 2 2 3 )3)(46.19( […]

Chapter 16 16.1 a. Eq. (16.2): 90.4%          )100( 08.18 35.16 RC (max) (field) d d b. Eq. (16.3): )1(1 RC AD A r  8.0 05.18 46.14 (max) (min)   […]

Chapter 2 2.1 d. kN/m 17.17 )05.0)(1000( 3 )81.9)(5.87( c. 3 kN/m 14.93      15.01 17.17 1w d a. Eq. (2.12): 0.76      e ee Gws ; 1 )81.9)(68.2( 14.93 . 1 […]

13 Chapter 3 3.1 Eq. (3.3): 8.96%    100 874.2 874.23 100(%) 2 22 2 22 i io RD DD A 3.2 Depth from ground surface (m) N60 cu (kN/m2) [Eq. (3.8)] o  (MN/m2) OCR [Eq. 3.9)] […]

Chapter 4 4.1 a. Eq. (4.8):    BNNqNcq qcu 2 1  = 28. Table 4.1: Nc = 31.61; Nq = 17.81; N = 13.7 2 lb/ft 5195       )7.13)(3)(110( 2 1 )81.17)(3)(110()61.31)(400( […]

Chapter 5 5.1 Eq. (5.3): **** 2 1sqsqu FBNFqNq  .40;6.0 5.1 m 9.0   B H Figures 5.4 and 5.5: 200 ;380 **   NNq Eqs. (5.4) and (5.5) and Figure 5.6: 688.0 5.2 5.1 )52.0(11 724.0 […]

Chapter 6 6.1 The following table can now be prepared. Note: B = 2 m (diameter); z = 3 m; qo = 150 kN/m2       2 B z r (m)      […]

55 Chapter 7 7.1 Eq. (7.1): s o eE Bq AAS 21  Df = 1.2 m; H = 3 m; B = 1.5 m; L = 3 m 8.0 5.1 2.1 ;2 5.1 3 ;2 5.1 3 B D […]

© 2016 Cengage Learning. All Rights Reserved. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part. Chapter 8 8.1 Eq. (8.12):          […]

75 Chapter 9 9.1 a. Eq. (9.16): lpqpp qANqAQ   * Given .42 2 From Table 9.5, q N = 525 kN 5.325,41)525)(206.18)(46.046.0( * qp NqA Eq. (9.17): kN 3.5001 )]42)(tan525)(100)(5.0)[(46.046.0( )tan5.0( 2 *    qaplp NpAqA […]

Chapter 9 86 2kN/m 49.623 )305.0( p wp A q So, mm 9.4m 004903.0)85.0)(3.01( 000,30 )305.0)(49.623(2 )2(         e s Again, from Eq. (9.84): wss s ws eI E D pL Q s)1( […]