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11.9 For the incompressible flow over a circular cylinder, from Eq. (3.101), Cp =
1 – 4 sin2 θ. Therefore, at the point of maximum velocity, Cp = -3. From the
Prandtl-Glauert rule,
From Eq. (11.60)
Equating Eqs. (1) and (2):
Solve for Mcr by trial-and-error.
Mcr Eq (1) Eq (2)
0.4 -3.2733 -3.66
